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4 years ago

10

classify the following energy sources as renewable and non-renewable energy sources (natural gas cool biomass and geothermal ene

rgy)

1 answer:

belka [17]4 years ago

3 0

Answer:

bio mass is renewable

natural gas non renewable geothermal energy renewable

Explanation:

biomass is by palnts and animals geothermals is unlimeted because its made out of the earths core

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the half-life of silicon-32 is 710 years. if 100 grams is present now, how much will be present in 300 years?

umka2103 [35]

The amount of Silicon left after 300 years is 75g

It is given that the initial amount of Si is 100 times decay is 300 years and the half-life of Silicon is 710 years.

The radioactive decay formula is given by,

A = A₀ x 2^(-t/h);

where;

A is the resulting amount after t time, Ao is the initial amt (t=0),t is the time of decay, and h is the half-life of the substance.

On substituting the values from the given we get,

A = 100x2^(-300/710)

A = 100 x 0.746112347

A = 74.6112347 grams left after 300 yrs

Therefore, the number of grams of silicon left after 300 years is 74.6112347g. This value could be rounded off to 75 grams as in the whole number

To know more about half-life, click below:

brainly.com/question/1160651

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3 0

2 years ago

The delocalized cloud of π electrons in benzene is formed by the overlap of 6 ________ orbitals.

Radda [10]

The delocalized cloud of π electrons in benzene is formed by the overlap of 6<u> p-orbitals</u>.

So, option B is correct one.

In the case of hydrocarbons, delocalisation occurs in benzene rings , where a hexagon of six carbon atoms has decalized electrons spread over the whole ring.

All of the carbon atoms in the benzene rings are $sp^{2}$ orbitals around the ring produces a framework of six sigma bonds, while the unhybridized p-orbitals which are perpendicular to this plane over in side-to-side fashion to form three pi-bonds.

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brainly.com/question/14525517

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8 0

2 years ago

Help me fill this out please, i give brainliest

xxTIMURxx [149]

Answer:

Okay, Left top= waning gibbous

left second= new moon

left third= third quarter

left fourth= waxing crescent

right top= Waning crescent

right second= first quarter

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right fourth= Waxing gibbous

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4 0

3 years ago

Read 2 more answers

Calculate the equilibrium constant for the following reaction: Co2+ (aq) + Zn(s> CO (s) + Zn2+ (aq)

Simora [160]

<u>Answer:</u> The $K_{eq}$ of the reaction is $1.73\times 10^{16}$

<u>Explanation:</u>

For the given half reactions:

Oxidation half reaction: $Zn(s)\rightarrow Zn^{2+}+2e^-;E^o_{Zn^{2+}/Zn}=-0.76V$

Reduction half reaction: $Co^{2+}+2e^-\rightarrow Co(s);E^o_{Co^{2+}/Co}=-0.28V$

Net reaction: $Zn(s)+Co^{2+}\rightarrow Zn^{2+}+Co(s)$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=-0.28-(-0.76)=0.48V$

To calculate equilibrium constant, we use the relation between Gibbs free energy, which is:

$\Delta G^o=-nfE^o_{cell}$

and,

$\Delta G^o=-RT\ln K_{eq}$

Equating these two equations, we get:

$nfE^o_{cell}=RT\ln K_{eq}$

where,

n = number of electrons transferred = 2

F = Faraday's constant = 96500 C

$E^o_{cell}$ = standard electrode potential of the cell = 0.48 V

R = Gas constant = 8.314 J/K.mol

T = temperature of the reaction = $25^oC=[273+25]=298K$

$K_{eq}$ = equilibrium constant of the reaction = ?

Putting values in above equation, we get:

$2\times 96500\times 0.48=8.314\times 298\times \ln K_{eq}\\\\K_{eq}=1.73\times 10^{16}$

Hence, the $K_{eq}$ of the reaction is $1.73\times 10^{16}$

8 0

3 years ago

What are septa?<br> This is in Zoology

valentinak56 [21]

<span> the part separating two chambers, such as that between the nostrils or the chambers of the heart</span>

6 0

3 years ago