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4 years ago

In which of the fire plume structure zones do the gases accelerate upward?

1 answer:

3 0

The zone that gases always accelerate upward is the Luminous flame zone. The fire plume is the column of hot gases, flames and smoke rising above a fire. Gases accelerate upward toward the always luminous flame zone. The luminous flame height is the distance between the base of a flame and the point at which the plume is luminous half the time and transparent half the time.

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Where is the chart option found in the Excel application?

vodomira [7]

Answer:

its under the insert table

Explanation:

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3 years ago

A mass weighing 16 pounds stretches a spring 8 3 feet. The mass is initially released from rest from a point 6 feet below the eq

Greeley [361]

Answer:I don’t know

Explanation:

7 0

4 years ago

EASY BRAINLIEST PLEASE HELP!!

jeka94

Answer:

Solution given:

frequency[f]=60,500,000Hz

velocity[V]=300,000,000m/s

wave length=?

we have

wave length= $\frac{V}{f}$

= $\frac{300,000,000}{60,500,000}$

= $\frac{3000}{605}$ =4.96 m

Option A.4.96m

3 0

3 years ago

Read 2 more answers

You are pushing this M = 115-kg box with Fa = 424 Newtons. (Fa = "Your applied force") But it's futile. The box isn't going anyw

lana66690 [7]

Explanation:

We have,

Mass of a box is 115 kg

Applied force is 424 N

It is required to find the frictional force of the floor on the box against you. Frictional force is an opposing force. It opposes the motion of an object. Here the applied force is 424 N. So, the frictional force has a magnitude of 424 N but it acts in opposite direction.

5 0

4 years ago

If the potential (relative to infinity) due to a point charge is V at a distance R from this charge, the distance at which the p

AfilCa [17]

Answer:

R/2

Explanation:

The potential at a distance r is given by :

$V=\dfrac{kq}{r}$

Where

k is electrostatic constant

q is the charge

The potential (relative to infinity) due to a point charge is V at a distance R from this charge. So,

$\dfrac{V_1}{V_2}=\dfrac{r_2}{r_1}$

Put all the values,

$\dfrac{V}{2V}=\dfrac{r_2}{R}\\\\\dfrac{1}{2}=\dfrac{r_2}{R}\\\\r_2=\dfrac{R}{2}$

<h3>So, the distance at which the potential (relative to infinity) is 2V is R/2.</h3>

6 0

3 years ago