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Crank
3 years ago
8

Someone help me please if you don’t mind

Mathematics
2 answers:
Debora [2.8K]3 years ago
8 0

Answer:

x(3x^ x - 2 x - 1)

Step-by-step explanation:

valina [46]3 years ago
6 0

the answer is

x(3x^2 - 2x - 1)

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A quadrilateral has angles that measure 101°, 133°, and 76°.
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The last angle is 50°
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A variety of two types of snack packs are delivered to a store. The box plots compare the number of calories in each snack pack
adelina 88 [10]

OPTIONS:

A. The interquartile range of the trail mix data is greater than the range of the cracker data.

B. The value 70 is an outlier in the trail mix data.

C. The upper quartile of the trail mix data is equal to the maximum value of the cracker data.

D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

Answer:

D.

Step-by-step explanation:

With the given information about how the box plot looks like, let's examine each option to see if they are true or not.

<u><em>Option A: "The interquartile range of the trail mix data is greater than the range of the cracker data."</em></u>

The interquartile range of trail mix data = 105 - 90 = 15

Range of cracker data = 100 - 70 = 30

Option A is NOT TRUE.

<u><em>Option B: "The value 70 is an outlier in the trail mix data.</em></u>"

This is NOT TRUE. There are not outliers as 70 is the minimum value if the ranges of the data set for the trail mix.

<em><u>Option C: "The upper quartile of the trail mix data is equal to the maximum value of the cracker data."</u></em>

Upper quartile of the trail mix data = 105

Max value of cracker data = 100

This statement is NOT TRUE.

<em><u>Option D: "The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers."</u></em>

The greater the range value, the greater the variation. Thus,

Range value of the trail mix data = 115 - 70 = 45

Range value of the cracker data = 100 - 70 = 30

This is statement is correct because trail mix data have a greater range value, hence, it has a greater variation in the number of calories.

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Answer:

879

Step-by-step explanation:

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There is nothing there

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Explain how you could convert a rate of 18000 miles per hour to miles per second
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You could multiply that fraction by (1 hour / 3,600 seconds) .

               (18,000 mile / 1 hour) x (1 hour / 3,600 second) = 

               (18,000 x 1) / (1 x 3,600)  (mile-hour) / (hour-second) = 

                     (18,000 / 3,600)  (mile / second)  =  <span>5 mile/second
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