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3 years ago

HELP PLS MARKING BRANLIST 100 Pts TAKING TEST RN

Physics

2 answers:

FromTheMoon [43]3 years ago

6 0

Answer:

A. 1.90

I divided 63 by 60 and got 1.05

I multiplied 1.05 by 2 (120 seconds = 2 minutes) and I got 2.1

1.90 is the closest answer.

Bumek [7]3 years ago

5 0

Answer:

It will travel 7,560 m

Explanation:

63 x 120 = 7,560 m

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if a 10kg object is lifted a distance of 10m from the rest what was the final velocity of the object?

Anastasy [175]

I think it will be 100 kg

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3 years ago

Two coaxial conducting cylindrical shells have equal and opposite charges. The inner shell has charge +q and an outer radius a,

Leviafan [203]

Answer:

$\Delta V = \frac{q ln(\frac{b}{a})}{2\pi \epsilon_0 L}$

Explanation:

As we know that the charge per unit length of the long cylinder is given as

$\lambda = \frac{q}{L}$

here we know that the electric field between two cylinders is given by

$E = \frac{2k\lambda}{r}$

now we know that electric potential and electric field is related to each other as

$\Delta V = - \int E.dr$

$\Delta V = -\int_a^b (\frac{2k\lambda}{r})dr$

$\Delta V = -2k \lambda ln(\frac{b}{a})$

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$\Delta V = \frac{q ln(\frac{b}{a})}{2\pi \epsilon_0 L}$

7 0

3 years ago

Calculate the area of a square with a length of 5cm

mihalych1998 [28]

Answer:

25cm^2

Explanation:

area of square = side × side

length of side given = 5

area of this square = 5× 5

= 25cm^2

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3 years ago

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Which climate condition is typically found in the tropics due to the interaction of the atmosphere and hydrosphere?

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The answer is A! Hope I helped!

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3 years ago

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Two paths lead to the top of a big hill. One is steep and direct, while the other is twice as long but less steep. How much more

umka2103 [35]

Answer:

None.

Explanation:

Gravitational potential energy, depends only of the mass on which the gravity is doing work, and the displacement produced by this force.
As displacement depends only on the final and initial positions (in this case, the height of the hill), if we choose as our zero reference level the bottom of the hill, the change in gravitational potential energy will be as follows:

$\Delta U = U_{f} -U_{0} = m*g*h - 0 = m*g*h$

As we can see, the only value of distance involved is the height of the hill , so it is independent of the distance travelled.

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4 years ago