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mart [117]
2 years ago
7

Que animales respiran por las branquias​

Physics
2 answers:
Yakvenalex [24]2 years ago
7 0

Answer:

what animals breathe through gills

Explanation:

Ivan2 years ago
5 0

Answer:

el Tiburon

Explanation:

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!!!!!!PLEASE HELP ASAP !!!!!!!!!!!!
OLga [1]

Answer: d constint speed

Explanation: im 15 and no the answer

5 0
2 years ago
A 10-cm-long wire is pulled along a u-shaped conducting rail in a perpendicular magnetic field. the total resistance of the wire
Debora [2.8K]

In the above case we can say that power given by external agent to pull the rod must be equal to the power dissipated in the form of heat due to magnetic induction.

Part a)

when we pull the rod with constant speed then power required will be product of force and velocity

here we will have

P = F.v

P = 4 W

v = 4 m/s

now we will have

4 = F*4

F = 1N

So external force required will be 1 N

PART B)

now in order to find magnetic field strength we can say

P = \frac{v^2B^2L^2}{R}

here we know that induced EMF in the wire is E = vBL

so power due to induced magnetic field is given by

P = \frac{E^2}{R}

4 = \frac{4^2*B^2*0.10^2}{0.20}

by solving above equation we will have

B = 2.24 T

5 0
3 years ago
What is the speed of a car going v=1.000mph in SI units? Notice that you will need to change from miles to meters and from hours
Paha777 [63]

Answer: speed = 446.4m/s

Explanation: 1000mph implies that 1000 miles / 1 hour.

But it has been given that 1mile = 1609m,

hence

1000 miles = 1000 * 1609 = 1,609,000m

And I hour = 3600s

Hence 1000mph = 1,609,000/ 3600

1000 = 446.4m/s

5 0
2 years ago
A 25-foot ladder is leaning against a house. The base of the ladder is pulled away from the house at a rate of 2 feet per second
grandymaker [24]

A ladder 25 feet long is leaning against a house.  The base of the ladder is pulled away at a rate of 2 ft/sec.  

a.)  How fast is the top of the ladder moving down the wall when the base of the ladder is 12 feet from the wall?

Answer:

dy/dt = -1.094ft/sec

Explanation:

Given that:

dz/dt = 0,

dx/dt = 2,

dy/dt = ?

Hence, we have the following

Using Pythagoras theorem

We have 25ft as the hypotenuse, y as the opposite or height of wall, and x as the base of the triangle

X² + y² = z²,

12² + y² = 25²,

y² = 25² - 12²

y = √481

Therefore, we have the following:

2x dx/dt + 2y dy/dt,

= 2z dz/dt,

= 12 (2) √481 dy/dt,

= √481 dy/dt = -24,

= dy/dt = -1.094ft/sec

Therefore, final answer is -1.094ft/sec

4 0
2 years ago
A certain freely falling object, released from rest, requires 1.50 s to travel the last 30.0 m before it hits the ground. From w
BaLLatris [955]

Answer:

The object fell from about 38.14 meters

Explanation:

We can use the formula for displacement under accelerated motion due to gravity to find the velocity of the object had 30 m before hitting the ground :

y_f-y_i=v_i * \,t-\frac{9.8}{2} \,t^2\\0-30=v_i \,(1.5)-4.9\,(1.5)^2\\-18.975=v_i\,(1.5)\\v_i=-12.65\,\,\frac{m}{s}

Now, knowing this velocity, we can find the time it took to fall from the initial position to 30 m before hitting the ground:

v_f=v_i-g\,*\,t\\-12.65=0-g \,*\,t\\t=\frac{12.65}{g} \\t\approx1.29\,\,s

And now we can find what is the total distance covered in 1.5 s plus 1.29 seconds for this free falling object:

y_f-y_i=v_i * \,t-\frac{9.8}{2} \,t^2\\0-y_i=0-\frac{9.8}{2} \,(2.79)^2\\-y_i=-38.14\\y_i=38.14\,\,m

7 0
2 years ago
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