The momentum of the water balloon at the given speed is 7.2 kgm/s.
The given parameters:
- <em>Speed of the water balloon, v = 18 m/s</em>
- <em>Mass of the balloon, m = 0.4 kg</em>
The momentum of the water balloon is calculated as follows;
P = mv
<em>Substitute the given values of </em><em>mass </em><em>and </em><em>velocity </em><em>as follows;</em>
P = 0.4 x 18
P = 7.2 kg m/s.
Thus, the momentum of the water balloon at the given speed is 7.2 kgm/s.
Learn more about momentum here: brainly.com/question/7538238
Answer;
-A model
Explanation;
-A mathematical model is an abstract model that uses mathematical language to describe the behavior of a system. A Mathematical Model tries to copy how a real world thing works using equations.
-Usually a mathematical model describes a system by a set of variables and a set of equations that establish relationships between the variables. Variables may be of many types; real or integer numbers, for example.
-The Area A of a circle with radius r is given by the formula A = πr2. In this formula π ≈ 3.1416... is a number which is a constant, and A and r are variables or unknowns. A is called the subject of the formula.
Answer:
91.64 km
91.64 km high material would go on earth if it were ejected with the same speed as on Io.
Explanation:
According to Newton Law of gravitation:

Where:
G is gravitational constant=
For Moon lo g is:

According to law of conservation of energy
Initial Energy=Final Energy


For Jupiter's moon Io:
Velocity is given by:

For Earth Velocity is given by:

Now:





91.64 km high material would go on earth if it were ejected with the same speed as on Io.
Momentum = (mass) x (velocity)
Original momentum before the hit =
(0.16 kg) x (38 m/s) this way <==
= 6.08 kg-m/s this way <==
Momentum after the hit =
(0.16) x (44 m/s) that way ==>
= 7.04 kg-m/s that way ==>
Change in momentum = (6.08 + 7.04) = 13.12 kg-m/s that way ==> .
-----------------------------------------------
Change in momentum = impulse.
Impulse = (force) x (time the force lasted)
13.12 kg-m/s = (force) x (0.002 sec)
(13.12 kg-m/s) / (0.002 sec) = Force
6,560 kg-m/s² = 6,560 Newtons = Force
( about 1,475 pounds ! ! ! )
Frequency = rate of sploosh = 2 per second = 2 Hz.
Period = ( 1/frequency ) = 1/2 second
Speed = (wavelength) x (frequency) = (0.15m) x ( 2/sec) = 0.075 m/s .