120 grams of NaOH means 3 Moles of NaOH because 40 grams (Molecular Weight in grams) is one mole of NaOH.
Each mole of any substance contain Avogadro’s number of molecules ie., 6.022 x (10 to the power 23).
Hence 3 Moles of NaOH contain 3 times of Avogadro’s number of molecules ie., 3 x 6.022 x (10 to the power 23)
Answer:
The temperature change from the combustion of the glucose is 6.097°C.
Explanation:
Benzoic acid;
Enthaply of combustion of benzoic acid = 3,228 kJ/mol
Mass of benzoic acid = 0.570 g
Moles of benzoic acid = ![\frac{0.570 g}{122.12 g/mol}=0.004667 mol](https://tex.z-dn.net/?f=%5Cfrac%7B0.570%20g%7D%7B122.12%20g%2Fmol%7D%3D0.004667%20mol)
Energy released by 0.004667 moles of benzoic acid on combustion:
![Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J](https://tex.z-dn.net/?f=Q%3D3%2C228%20kJ%2Fmol%20%5Ctimes%200.004667%20mol%3D15.0668%20kJ%3D15%2C066.8%20J)
Heat capacity of the calorimeter = C
Change in temperature of the calorimeter = ΔT = 2.053°C
![Q=C\times \Delta T](https://tex.z-dn.net/?f=Q%3DC%5Ctimes%20%5CDelta%20T)
![15,066.8 J=C\times 2.053^oC](https://tex.z-dn.net/?f=15%2C066.8%20J%3DC%5Ctimes%202.053%5EoC)
![C=7,338.92 J/^oC](https://tex.z-dn.net/?f=C%3D7%2C338.92%20J%2F%5EoC)
Glucose:
Enthaply of combustion of glucose= 2,780 kJ/mol.
Mass of glucose=2.900 g
Moles of glucose = ![\frac{2.900 g}{180.16 g/mol}=0.016097 mol](https://tex.z-dn.net/?f=%5Cfrac%7B2.900%20g%7D%7B180.16%20g%2Fmol%7D%3D0.016097%20mol)
Energy released by the 0.016097 moles of calorimeter combustion:
![Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J](https://tex.z-dn.net/?f=Q%27%3D2%2C780%20kJ%2Fmol%20%5Ctimes%200.016097%20mol%3D44.7491%20kJ%3D44%2C749.1%20J)
Heat capacity of the calorimeter = C (calculated above)
Change in temperature of the calorimeter on combustion of glucose = ΔT'
![Q'=C\times \Delta T'](https://tex.z-dn.net/?f=Q%27%3DC%5Ctimes%20%5CDelta%20T%27)
![44,749.1 J=7,338.92 J/^oC\times \Delta T'](https://tex.z-dn.net/?f=44%2C749.1%20J%3D7%2C338.92%20J%2F%5EoC%5Ctimes%20%5CDelta%20T%27)
![\Delta T'=6.097^oC](https://tex.z-dn.net/?f=%5CDelta%20T%27%3D6.097%5EoC)
The temperature change from the combustion of the glucose is 6.097°C.
Answer:
Explanation:
{\displaystyle {}^{n}x}{}^{n}x, for n = 2, 3, 4, …, showing convergence to the infinitely iterated exponential between the two dots
In mathematics, tetration (or hyper-4) is an operation based on iterated, or repeated, exponentiation. It is the next hyperoperation after exponentiation, but before pentation. The word was coined by Reuben Louis Goodstein from tetra- (four) and iteration.
Under the definition as repeated exponentiation, the notation {\displaystyle {^{n}a}}{\displaystyle {^{n}a}} means {\displaystyle {a^{a^{\cdot ^{\cdot ^{a}}}}}}{\displaystyle {a^{a^{\cdot ^{\cdot ^{a}}}}}}, where n copies of a are iterated via exponentiation, right-to-left, I.e. the application of exponentiation {\displaystyle n-1}n-1 times. n is called the "height" of the function, while a is called the "base," analogous to exponentiation. It would be read as "the nth tetration of a".
Tetration is also defined recursively as
{\displaystyle {^{n}a}:={\begin{cases}1&{\text{if }}n=0\\a^{\left(^{(n-1)}a\right)}&{\text{if }}n>0\end{cases}}}{\displaystyle {^{n}a}:={\begin{cases}1&{\text{if }}n=0\\a^{\left(^{(n-1)}a\right)}&{\text{if }}n>0\end{cases}}},
allowing for attempts to extend tetration to non-natural numbers suc
The general formula of an acid is HX where H+ acts as the cation while X can be a halogen (Cl-, Fl-, Br-, etc) and acts as the anion. There are also cases where X is an ion like SO42-, which brings two atoms of H in the formula. Strong acids dissociate completely while weak acids do not.