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mihalych1998 [28]
3 years ago
12

Playing catch with a friend in a moving train. When you toss the ball in the direction the train is moving, how does the speed o

f the ball appear to an observer standing at rest outside the train?
I understand basic relative motion, just the ball moving on another moving object confuses me!
Physics
2 answers:
likoan [24]3 years ago
5 0
Well it would simply appear faster because the speed of the ball and the speed of the train.
telo118 [61]3 years ago
5 0

Answer:

The speed of the ball appear faster when we observe it from ground frame at rest.

Explanation:

As we know that by relate motion concept

v_{AB} = v_A - v_B

here when ball is thrown in the direction of train motion with velocity "v" relative to the train then we will assume here that let say the train at that moment is running at speed v_T

now by above concept of relative velocity we will have

v = v_{ball} - v_T

now for the speed of ball

v_{ball} = v + v_T

so from this equation we can see that the actual speed of ball in ground frame will be more than the speed observed in train frame

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3 years ago
A bullet is shot vertically upward with an initial velocity of 128 ft/s. The bullet's height after t seconds is y(t) = 128t - 16
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The height of the bullet when the velocity is zero is 256 ft.

<h3>Height of the bullet when the velocity is zero </h3>

The height of the bullet when the velocity is zero is determined by taking derivative of the function as shown below;

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The height of the bullet at this time is calculated as follows;

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Learn more about height of projectiles here: brainly.com/question/10008919

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