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3 years ago

How are steam powered boats different from sailboats

2 answers:

6 0

Hi there!

Steam powered boats use steam to propel and move the boat, while sailboats rely in the angle of the sail and the wind to move and turn.

Hope this helps!

Alex3 years ago

3 0

Steam powered boats run from an engine, using power, gears, and cranks to function.

Sailboats use no engine and rely on winds to move and change the direction of the boat.

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If a ball is dropped from a height of 10 m, hits the ground and bounces back up to a maximum height of 7.5 m, describe how the E

Greeley [361]

Answer:hmmmm

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3 years ago

The energy delivered to the resistive coil is dissipated as heat at a rate equal to the power input of the circuit. However, not

Nuetrik [128]

Answer:

P(bat) = V²r/(R+r)²

Explanation:

Let the resistance of the coil be R

Internal resistance of the battery be r

Emf of the battery = V

Power dissipated in the internal resistance of the battery is normally given as P = I²r

where I is the current flowing in the circuit.

From Ohm's law,

V = I R(eq)

R(eq) = (R + r)

I = V/(R+r)

P = I²r

P = [V/(R+r)]²r

P = V²r/(R+r)²

Hope this Helps!!!

6 0

3 years ago

The tension in the horizontal towrope pulling a water-skier is 250 N while the skier moves due west a distance of 50 m. How much

icang [17]

Answer:

W = 250(50) = 12500 J

Explanation:

5 0

3 years ago

What is the distance traveled when a car goes 20 m/s for 60 seconds?

AfilCa [17]

Answer:

1200 m

Explanation:

s= vt

s= 20m/s × 60 s

s= 1200 m

hope it hepls

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5 0

3 years ago

A barbell consists of two small balls, each with mass m at the ends of a very low mass rod of length d. The barbell is mounted o

sveta [45]

The total angular momentum of the system about point B is $L=m_1r_1\omega_1+m_2r_2\omega_2$

Angular momentum, also known as moment of momentum or rotational momentum, is the rotating counterpart of linear momentum.

A rigid object's angular momentum is defined as the product of its moment of inertia and its angular velocity. If there is no external torque on the object, it is analogous to linear momentum and is subject to the fundamental constraints of the conservation of angular momentum principle. The vector quantity angular momentum It is derived from the expression for a particle's angular momentum.

Given,

mass of ball 1 = m1

m₂ mass of ball 2=m2

v₁ is the velocity of ball=r₁ω₁

v₂ is the velocity of ball 2=r₂ω₂

The total angular momentum is given as;

$V_{total}=r_1\omega_1+r_2\omega_2\\\\L=m_1r_1\omega_1+m_2r_2\omega_2$

Hence the total angular momentum will be $L=m_1r_1\omega_1+m_2r_2\omega_2$

To learn more about angular momentum refer here

brainly.com/question/29512279

#SPJ4

6 0

1 year ago