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3 years ago

A(-6)=-42 solve for a

Mathematics

2 answers:

Arte-miy333 [17]3 years ago

6 0

Answer:

Step-by-step explanation:

Orlov [11]3 years ago

3 0

Answer:

A = 7

Step-by-step explanation:

You would take -42/-6 because that will tell you what x -6=-42

-42/-6 = 7

Also. you have to remember that a negative divided or multiplied by a negative = a positive

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Copies of a famous painting were created at the local art museum for visitors to purchase. The copies had a 30% smaller area tha

lina2011 [118]

Answer:

12.6 square feet

Step-by-step explanation:

So first we set it up:

18ft is 100% of the original

and the area of the copies are 70%

Copies: x

x/70 = 18/100

70(18) = 1260

1260/100 = 12.6

x = 12.6

6 0

3 years ago

The graph of the continuous function g, the derivative of the function f, is shown above. The function g is piecewise linear for

4vir4ik [10]

A) $g=f'$ is continuous, so $f$ is also continuous. This means if we were to integrate $g$ , the same constant of integration would apply across its entire domain. Over $0$ , we have $g(x)=2x$ . This means that

$f_{0$

For $f$ to be continuous, we need the limit as $x\to1^-$ to match $f(1)=3$ . This means we must have

$\displaystyle\lim_{x\to1}x^2+C=1+C=3\implies C=2$

Now, over $x$ , we have $g(x)=-3$ , so $f_{x$ , which means $f(-5)=17$ .

b) Integrating over [1, 3] is easy; it's just the area of a 2x2 square. So,

$\displaystyle\int_1^6g(x)=4+\int_3^62(x-4)^2\,\mathrm dx=4+6=10$

c) $f$ is increasing when $f'=g>0$ , and concave upward when $f''=g'>0$ , i.e. when $g$ is also increasing.

We have $g>0$ over the intervals $0$ and $x>4$ . We can additionally see that $g'>0$ only on $0$ and $x>4$ .

d) Inflection points occur when $f''=g'=0$ , and at such a point, to either side the sign of the second derivative $f''=g'$ changes. We see this happening at $x=4$ , for which $g'=0$ , and to the left of $x=4$ we have $g$ decreasing, then increasing along the other side.

We also have $g'=0$ along the interval $-1$ , but even if we were to allow an entire interval as a "site of inflection", we can see that $g'>0$ to either side, so concavity would not change.

5 0

3 years ago

Help needed on this composition math problem

Marrrta [24]

Given that f(x) = x/(x - 3) and g(x) = 1/x and the application of <em>function</em> operators, f ° g (x) = 1/(1 - 3 · x) and the domain of the <em>resulting</em> function is any <em>real</em> number except x = 1/3.

<h3>How to analyze a composed function</h3>

Let be f and g functions. Composition is a <em>binary function</em> operation where the <em>variable</em> of the <em>former</em> function (f) is substituted by the <em>latter</em> function (g). If we know that f(x) = x/(x - 3) and g(x) = 1/x, then the <em>composed</em> function is:

$f\,\circ\,g \,(x) = \frac{\frac{1}{x} }{\frac{1}{x}-3}$

$f\,\circ\,g\,(x) = \frac{\frac{1}{x} }{\frac{1-3\cdot x}{x} }$

$f\,\circ\,g\,(x) = \frac{1}{1-3\cdot x}$

The domain of the function is the set of x-values such that f ° g (x) exists. In the case of <em>rational</em> functions of the form p(x)/q(x), the domain is the set of x-values such that q(x) ≠ 0. Thus, the domain of f ° g (x) is $\mathbb{R} - \{\frac{1}{3} \}$ .

To learn more on composed functions: brainly.com/question/12158468

#SPJ1

3 0

2 years ago

A water tank that holds 30 gallons of water when full is leaking 3/4 gallon of water every hour. If no one notices and stops the

viva [34]

It will take 40 hours for the water tank to become empty.

Explanation:
Divide 30 by 0.75 (equivalent to 3/4).

7 0

3 years ago

You see a news headline which claims that tuition at CSU San Jose is going to increase by 7% next year. If tuition for in-state

wolverine [178]

The tuition would be $6143.94 next year

<h3>How to detemrine the tuition amount?</h3>

The given parameters are:

Current amount = $5,742
Rate of increment, r = 7%

The tuition next year is then calculated as:

Tuition = Current * (1 + Rate)

This gives

Tuition = $5,742 * (1 + 7%)

Evaluate

Tuition = $6143.94

Hence, the tuition would be $6143.94 next year