Ask question

Ask question

All categories

Misha Larkins [42]

3 years ago

15

Can someone help me with the motion maps, I don't understand what I am supposed to write in the description or how to draw the a

rrows on the maps. 50 points!!!

1 answer:

Ugo [173]3 years ago

7 0

Answer:

i d k

Explanation:

You might be interested in

A tsunami is a large wave that is caused by

marysya [2.9K]

An earthquake or disturbance undersea.

~ThePirc

5 0

3 years ago

Read 2 more answers

Action and reaction forces are described by which of Newton’s laws of motion?

nikdorinn [45]

Answer:

third

Explanation:

for every action there is an equal and opposite reaction

example

bouncing ball

ball receives a force from the ground due to collision

that same force causes the ball to bounce off the ground

first law:

inertia

example

stuff in space doesn't move unless its pushed

then it keeps going unless something stops it

second law

force = mass times acceleration

example

harder you push a cart the faster it goes

the less a cart weighs the faster a cart goes

studysmarterus

spacecenterorg

energywavetheory

5 0

3 years ago

Question 8 a-e plz

N76 [4]

Answer:

(a) t = 0 s

(b) t = 0 s, 30 s, 55 s

(c) t = 40 s to t = 60 s

(d) t = 10 s to t = 15 s

(e) a = 6 m/s^2

Explanation:

(a) The car is at starting position at t = 0 s and v = 0 m/s.

(b) The velocity of car is zero when the time is t = 0 s, 30 s and 55 s.

(c) from t = 40 s to 60 s the car is moving in the negative direction.

(d) The fastest speed is 60m/s from t = 10 s to t = 15 s.

(e) The slope of the velocity time graph gives acceleration.

a = (60 - 0) / (10 - 0) = 6 m/s^2

5 0

3 years ago

Let's say you are on the third story of an apartment building that has a swimming pool. For some insane reason you think it is a

labwork [276]

Answer:

To make it into the pool you must run and jump at

$\displaystyle v_o=x.\sqrt{\frac{g}{2y}}$

Explanation:

Horizontal Launch

When an object is thrown with a specified initial speed in the horizontal direction, it describes a curved path that finishes when it hits the ground level after traveling certain horizontal distance x and a vertical height y from the launching point. The horizontal speed is always constant and the vertical speed increases due to the effect of gravity. It can be found that the horizontal distance reached by the object when launched at an initial speed in a given time t is

$x=v_o.t$

And the vertical distance is

$\displaystyle y=\frac{g.t^2}{2}$

If t is the total flight time, then x and y are maximum and we can find a relation between them. Solving for t in the first equation

$\displaystyle t=\frac{x}{v_o}$

Substituting in the second equation

$\displaystyle y=\frac{g}{2}\left ( \frac{x}{v_o}\right )^2$

Rearranging

$\displaystyle \left ( \frac{v_o}{x}\right )^2=\frac{g}{2y}$

Solving for $v_o$

$\displaystyle v_o=x.\sqrt{\frac{g}{2y}}$

There are many applications for the horizontal launch. One common situation is when someone wants to drop something on certain terrain at a specific approximate point when traveling in a plane at a given height. Once the object is left fall, it has the same speed as the plane, so the plane speed can be estimated to make the best possible launch, or given that speed, we can know in advance where the object will reach ground level

4 0

3 years ago

A 12.0 kg object is attached to a cord that is wrapped around a wheel of radius 10.0 cm. the acceleration of the object down the

olganol [36]

a) We use the formula:

T = [g sinθ – a] * m

where g is gravity, θ is the angle, a is acceleration, m is mass

T = [9.81 sin37 - 2.00] * 12 = 46.85 N <span>

b) We use the formula for moment of interia:</span>

I = T * r² / a

I = 46.85 * 0.10² / 2.00 = .2343 kg∙m² <span>

c) The formula we can use here is:</span>

w = α * t = (a/r) * t

w = (2/.10) * 2

<span>w = 40 rad/sec</span>

6 0

3 years ago