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Misha Larkins [42]

3 years ago

15

Can someone help me with the motion maps, I don't understand what I am supposed to write in the description or how to draw the a

rrows on the maps. 50 points!!!

1 answer:

Ugo [173]3 years ago

7 0

Answer:

i d k

Explanation:

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a child in a tree house uses a rope attached to a basket to lift a 26 nn dog upward through a distance of 5.0 mm into the house.

agasfer [191]

Total work done is 0.13 Joules

<h3>What is work done ?</h3>

The sum of the displacement and the component of the applied force of the object in the displacement direction is the work done by a force.

According to the given information

We need to find the work done

work done = force × distance

We are given,

force = 26 N

Distance = 0.0005 meter

hence ,

Work done = 26 × 0.005

= 0.13 Joules

Total work done is 0.13 Joules

To know more about Work done

brainly.com/question/13662169

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4 0

1 year ago

Physical quantity are measurable quantities

Vilka [71]

Answer:

yeah physical quantities are the quantities which can be meaured

7 0

3 years ago

the moon revolves around the earth in a nearly circular orbit kept by gravitational force exerted by the earth work done will be

rodikova [14]

Answer:

Zero because the applied force is perpendicular to the motion of the object.

No work is done on an object moving is a circular path about a central attractive force.

Any work done in such a case would result in a change in the orbit.

3 0

2 years ago

Consider two objects (Object 1 and Object 2) moving in the same direction on a frictionless surface. Object 1 moves with speed v

d1i1m1o1n [39]

1) A) Object 1 has the greater momentum

The magnitude of the momentum of an object is given by:

$p=mv$

where

m is the mass of the object

v is its speed

Object 1 has a mass of $m_1 = 2m$ and a speed of $v_1 = v$ , so its momentum is

$p_1 = m_1 v_1 = (2m)(v)=2mv$

Object 2 has a mass of $m_2 = m$ and a speed of $v_2 = \sqrt{2} v$ , so its momentum is

$p_2 = m_2 v_2 = (m)(\sqrt{2} v)=\sqrt{2}mv$

So we see that $p_1 > p_2$ , so object 1 has the greater momentum.

2) The objects have the same kinetic energy.

The kinetic energy of an object is given by

$K=\frac{1}{2}mv^2$

where

m is the mass of the object

v is its speed

Object 1 has a mass of $m_1 = 2m$ and a speed of $v_1 = v$ , so its kinetic energy is

$K_1 = \frac{1}{2}m_1 v_1^2 = \frac{1}{2}(2m)(v)^2=mv^2$

Object 2 has a mass of $m_2 = m$ and a speed of $v_2 = \sqrt{2} v$ , so its kinetic energy is

$K_2 = \frac{1}{2}m_2 v_2^2 = \frac{1}{2}(m)(\sqrt{2} v)^2=mv^2$

So we see that $K_1 =K_2$ , so the objects have same kinetic energy

5 0

3 years ago

When a user wants to participate in a PKI, what component does he or she need to obtain, and how does that happen?

Luba_88 [7]

Answer: certificate authority

Explanation: The user submits Identification data and certificate request to the registration authority (RA). The RA validates this information and sends the certificate request to the certificate Authority (CA)

5 0

3 years ago