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mojhsa [17]
3 years ago
9

Group 13 elements tend to have what charge

Chemistry
2 answers:
Alexandra [31]3 years ago
8 0

Answer:

+3

Explanation:

Because elements of group 13 have 3 valence electrons they loses them and show +3 charge

Like Al3+

umka21 [38]3 years ago
6 0

Answer:

+3

Explanation:

cause im smart........

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By mistake, you added salt instead of sugar to the<br> oil. How can you remove the salt?
Jet001 [13]

Answer:

by adding water into the mix

Explanation:

this will dissolve the salt

5 0
2 years ago
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The monomer of poly(vinyl chloride) has the formula C2H3Cl. If there are 1,565 repeat units in a single chain of the polymer, wh
monitta

Answer:

\large \boxed{9.780 \times 10^{4}\text{ u}}

Explanation:

The molecular mass of a monomer unit is:

C₂H₃Cl = 2×12.01 + 3×1.008 + 35.45 = 24.02 + 3.024 + 35.45 = 62.494 u

For 1565 units,

\text{Molecular mass} = \text{1565 units} \times \dfrac{\text{62.494 u}}{\text{1 unit }} = \mathbf{9.780 \times 10^{4}}\textbf{ u}\\\\\text{The molecular mass of the chain is $\large \boxed{\mathbf{9.780 \times 10^{4}}\textbf{ u}}$}

8 0
2 years ago
In your own words, describe two conditions that are necessary for an eclipse to occur
Rzqust [24]
1. the Moon must be in line with the Earth and Sun - New Moon for a solar eclipse and Full Moon for a lunar eclipse.2. the Moon must be at one of its nodes. Most of the time the Moon at New or Full passes above or below the Sun because its orbit is tilted relative to the ecliptic. An eclipse can occur only when it is at a node, in other words crossing the ecliptic.
4 0
3 years ago
What volume (in liters) does 3.91 moles of nitrogen gas at 5.35 atm and 323 K occupy
daser333 [38]
Moles   =  n  = 3.91 mol

                  Pressure  =  P  =  5.35 atm

                  Temperature  =  T  =  323 K

                  Volume  =  V  =  ?

Formula used: Ideal Gas Equation is used,

                                        P V  = n R  T
Solving for V,
                                           V  =  n R T / P
Putting Values,
                           V  =  (3.91 mol × 0.0825 atm.L.mol⁻¹.K⁻¹ × 323 K) ÷ 5.35 atm

                         V  =  19.36 L

5 0
3 years ago
How many grams Glycylglycine (molecular mass 132.119 grams/mole) are required to make 1 liter at 0.5 Molar concentration. If you
SOVA2 [1]

Explanation:

The given data is as follows.

        Concentration of solution = 0.5 M

        Volume of solution = 1 L

Molar mass of Glycylglycine = 132.119 g/mol

As molarity is the number of moles present in liter of solvent.

Mathematically,      Molarity = \frac{\text{No. of moles}}{\text{Volume}}

Hence, calculate the number of moles as follows.

            No. of moles = Molarity × Volume

                                  = 0.5 M \times 1 L

                                  = 0.5 mol

Therefore, mass of glycylglycine = mol × molar mass

                                                      = 0.5 mol \times 132.119 g/mol

                                                      = 66.06 g

Thus, we can conclude that 66.06 g glycylglycine is required.

8 0
3 years ago
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