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GuDViN [60]
3 years ago
6

The average kinetic energy of the particles with two pieces of iron at the same temperature and mass would be:

Physics
1 answer:
Aleks04 [339]3 years ago
7 0

Explanation:

5vfvnuj6ynjtntjunjtu

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An ideal monatomic gas expands isobarically, doubling the volume, from a state A to state B. It is then compressed isothermally
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B because I just think it’s the right answer because drawing a PV diagram for this cycle is the best answer even though it might be a stupid so I would not pay attention to my response because I’m just getting this for points but let me know if it is the right answer because right now I’m just guessing.
8 0
4 years ago
An object undergoing simple harmonic motion has amplitude of 2.3 m. if the maximum velocity of the object is 15 m/s, what is the
Eva8 [605]
Using:
v = Aωcos(ωt), at t = 0, A = 2.3 m and v = 15 m/s
ω = 15/2.3
ω = 6.52 rad/s
4 0
3 years ago
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An atom with 4 protons and 3 electrons has what overall charge?
Zielflug [23.3K]

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D

Explanation:

Because the protons with a positive charge outweigh the electrons with a negative charge by one

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3 years ago
Clouds absorb outgoing radiation emitted by Earth and retaliate a portion of it back to the surface during....
Ilia_Sergeevich [38]
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3 years ago
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A first year student projected a farm business brochure to a farmer at 30 degrees to horizontal. calculate the maximum height at
IceJOKER [234]

<u>Answer:</u>

Maximum height = 2040 m

<u>Explanation:</u>

We can solve the problem using kinematics.

Consider the vertical motion of the object and use the equation:

\boxed{v^2 = u^2 + 2as}

where:

• v = final velocity      (0 m/s, because when the object is at max. height, it has no vertical velocity)

• u = initial velocity    (400sin30° m/s ⇒ vertical component of 400 m/s at 30° to horizontal)

• a = acceleration      (-9.81 m/s²; considering upward acceleration to be negative)

• s = displacement    (? m; this represents the max. height of the object),

Substitute the values into the equation and solve for <em>s </em>:

0^2 = (400 sin (30 \textdegree))^2 + 2(-9.81)(s)

⇒ 2(9.81)(s) = (400 sin (30 \textdegree))^2

⇒  s = 2040 \space\ m     (3 s.f.)

6 0
2 years ago
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