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olganol [36]
2 years ago
14

HELP PLS and HURRY

Physics
1 answer:
tangare [24]2 years ago
5 0

Answer:

C - 50,000 * 77 * 3

Explanation:

At the top of the hill the potential energy is E= mgh= (160 kg)(9.81 m s^-2)(30 m)= 47088

hope it helps ,

<u>help me by marking as brainliest....</u>

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The amount of energy necessary to remove an electron from an atom is a quantity called the ionization energy, Ei. This energy ca
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Answer:

The value is E_i  =  1.5596 *10^{-18} \  J

Explanation:

From the question we are told that

The wavelength is \lambda  =  48.2 nm  =  48.2  *10^{- 9 }\  m

The velocity is v = 2.371*10^6 \ m/s

The mass of electron is m_e  =  9.109*10^{-31} \  kg

Generally the energy of the incident light is mathematically represented as

E =  \frac{h *  c}{\lambda}

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So

E =  \frac{6.62607015 *  10^{-34 }* 3.0 *10^{8}}{48.2  *10^{- 9 }}

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Generally the kinetic energy is mathematically represented as

E_k  =  \frac{1}{2} *  m_e * v^2

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Generally the ionization energy is mathematically represented as

E_i  =  4.12 *10^{-18} -   2.56 *0^{-18}

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3 years ago
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Answer:

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