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3 years ago

Biến tần là gì trong công nghiệp

1 answer:

Klio2033 [76]3 years ago

3 0

Nguồn điện là một yêu cầu thiết yếu của các ngành công nghiệp. Biến tần là một thiết bị độc lập có chức năng chuyển đổi điện áp một chiều thành điện áp xoay chiều. Biến tần đảm bảo rằng việc cung cấp điện không bị gián đoạn và liên tục. ... Các ngành công nghiệp yêu cầu sử dụng bộ nghịch lưu công nghiệp để hoạt động liên tục của các hoạt động trong ngành.

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Refer to the following distribution of commissions:Monthly Commissions Class Frequencies$600 up to $800 3800 up to 1,000 71,000

erica [24]

Answer:

21.81 %

Explanation:

given,

$600 up to $800 3

800 up to 1,000 7

$1,000 up to $1,200 11

$1,200 up to $1,400 12

$1,400 up to $1,600 40

$1,600 up to $1,800 24

$1,800 up to $2,000 9

$2,000 up to $2,200 4

Total = 3 + 7 + 11 + 12 + 40 + 24 + 9 + 4 = 110

the frequency of $1,600 to $1800

= $\dfrac{24}{110}$

=21.81 %

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3 years ago

Imagine you are designing a new backpack. Which of the following statement(s) about

Hoochie [10]

The answer is D.) both A and C

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3 years ago

Read 2 more answers

What is the maximum % carbon for structural steel?

Mkey [24]

Answer:

The large percentage of steel includes less than 0.35% carbon

Explanation:

Carbon is perhaps the most important business alloy of steel. Raising carbon material boosts strength and hardness and enhances toughness. However, carbon often increases brittleness.

The large percentage of steel includes less than 0.35% carbon. Any steel with a carbon content range of 0.35% to 1.86% can be considered as hardened.

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4 years ago

How do we need to prepare for the future?

Paraphin [41]

B. to achieve sustainable development

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3 years ago

The pressure distribution over a section of a two-dimensional wing at 4 degrees of incidence may be approximated as follows: Upp

Aliun [14]

Answer:

The lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

Explanation:

The Upper Surface Cp is given as

$Cp_u=-0.8 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.8*0.6+0.4*0.1$

The Lower Surface Cp is given as

$Cp_l=-0.4 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.4*0.6+0.4*0.1$

The difference of the Cp over the airfoil is given as

$\Delta Cp=Cp_l-Cp_u\\\Delta Cp=-0.4*0.6+0.4*0.1-(-0.8*0.6-0.4*0.1)\\\Delta Cp=-0.4*0.6+0.4*0.1+0.8*0.6+0.4*0.1\\\Delta Cp=0.4*0.6+0.4*0.2\\\Delta Cp=0.32$

Now the Lift Coefficient is given as

$C_L=\Delta C_p cos(\alpha_i)\\C_L=0.32\times cos(4*\frac{\pi}{180})\\C_L=0.3192$

Now the coefficient of moment about the leading edge is given as

$C_M=-0.3*0.4*0.6-(0.6+\dfrac{0.4}{3})*0.2*0.4\\C_M=-0.1306$

So the lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

5 0

3 years ago