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Sveta_85 [38]
2 years ago
5

Chemical engineering got is unofficial start around the time of the __________ __________ ________.

Engineering
1 answer:
Gre4nikov [31]2 years ago
4 0

Answer:

Option A,  World War II

Explanation:

During the period of industrial revolution around 1915-25, the chemical engineering has taken a new shape. During this period (i.e around the world war I), there was rise in demand for  liquid fuels, synthetic fertilizer, and other chemical products. This lead to development of chemistry centre in Germany . There was rise in use of synthetics fibres and polymers. World war II saw the growth of catalytic cracking, fluidized beds, synthetic rubber, pharmaceuticals production, oil & oil products, etc. and because of rising chemical demand, chemical engineering took a new shape during this period

Hence, option A is the right answer

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Water vapor at 100 psi, 500 F and a velocity of 100 ft./sec enters a nozzle operating at steady sate and expands adiabatically t
almond37 [142]

Answer:

a)exit velocity of the steam, V2 = 2016.8 ft/s

b) the amount of entropy produced is 0.006 Btu/Ibm.R

Explanation:

Given:

P1 = 100 psi

V1 = 100 ft./sec

T1 = 500f

P2 = 40 psi

n = 95% = 0.95

a) for nozzle:

Let's apply steady gas equation.

h_1 + \frac{(v_1) ^2}{2} = h_2 + \frac{(v_2)^2}{2}

h1 and h2 = inlet and exit enthalpy respectively.

At T1 = 500f and P1 = 100 psi,

h1 = 1278.8 Btu/Ibm

s1 = 1.708 Btu/Ibm.R

At P2 = 40psi and s1 = 1.708 Btu/Ibm.R

1193.5 Btu/Ibm

Let's find the actual h2 using the formula :

n = \frac{h_1 - h_2*}{h_1 - h_2}

n = \frac{1278.8 - h_2*}{1278.8 - 1193.5}

solving for h2, we have

h_2 = 1197.77 Btu/Ibm

Take Btu/Ibm = 25037 ft²/s²

Using the first equation, exit velocity of the steam =

(1278.8 * 25037) + \frac{(100)^2}{2}= (1197.77*25037)+ \frac{(V_2)^2}{2}

Solving for V2, we have

V2 = 2016.8 ft/s

b) The amount of entropy produced in BTU/ lbm R will be calculated using :

Δs = s2 - s1

Where s1 = 1.708 Btu/Ibm.R

At h2 = 1197.77 Btu/Ibm and P2 =40 psi,

S2 = 1.714 Btu/Ibm.R

Therefore, amount of entropy produced will be:

Δs = 1.714Btu/Ibm.R - 1.708Btu/Ibm.R

= 0.006 Btu/Ibm.R

3 0
3 years ago
Is an isothermal process necessarily internally reversible? Explain your answer with an example
torisob [31]

Answer:

please give me brainlist and follow

Explanation:

Example of an irreverseble isothermal process is mixing of two fluids on the same temperature - it requires a lot of energy to unmix Jack and coke. ... Example of an reversible process with changing temperature is isentropic expansion.

5 0
2 years ago
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Setler79 [48]
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3 years ago
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Why is it important to collect forensic evidence and witness accounts as soon as possible after an accident?
Orlov [11]

Answer:

If you have enough forensic evidence than you can be able to figure out who committed the accident or the burglary

Explanation:

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6 0
3 years ago
A controller for a satellite attitude control with transfer function G = 1 s 2 has been designed with a unity feedback structure
S_A_V [24]

Answer:

type 2, k = 4

Explanation:

(a) The transfer function of the controller for a satellite attitude control is  

G = \frac{1}{s^2}

The transfer function of unity feedback structure is

D(s) = \frac{10(s+2)}{s+5}  

To determine system type for reference tracking, identify the number of poles at origin in the open-loop transfer function.  

For unity feedback system, the open-bop transfer function

G(s)D_c(s)=\frac{1}{s^2}\frac{10(s+2)}{s+5}

                =\frac{10(s+2)}{s^2(s+5)}

Determine the poles in G(s)4(s).

s = 0,0,-5

Type of he system is decided by the number of poles at origin in the open loop transfer function.

Since, there are two poles at origin, the type of the system will be 2.  

Therefore, the system type is  

Type 2  

check the attached file for the concluding part of the solution

5 0
3 years ago
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