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pishuonlain [190]

2 years ago

7

Why do need engineer and architect

1 answer:

USPshnik [31]2 years ago

5 0

Answer: By using the expertise of an engineer or architect, a project can be built more efficiently and economically since the homeowner's vision can evolve on paper rather than during the building process. They also will work diligently with your budget and select materials and builders within your price point.

Explanation:

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please help me answer 3 of these questions in complete sentences. this is ccrd 1 related to jobs and college. thanks so much if

Kitty [74]

Answer:

1. Work is a driving force of identity in your life, whether its because it influences you due to the time spent there. Or its truly a passion of yours.

2. Two main aspects of identity development are self-concept and self-esteem

3. Based on you obviously

Hope this helped!

Explanation:

5 0

3 years ago

What is the measurement of this dial caliper? <br> A. 5.491<br> B. 4.044<br> C. 5.691

just olya [345]

Its C .......... .......... .......... .......... .......... .......... .......... .......... .......... .......... .......... ..........

4 0

3 years ago

How do I get my son to do his work?

valentinak56 [21]

Answer:

Explanation:

Reward him if he does his homework/work

If he doesnt do his homework, take things that he loves off of him. and tell him if he does his homework/work he will get them things back

8 0

3 years ago

3.94 x 105) + (2.04 x 105)

Flura [38]

627.9 is the answer

6 0

3 years ago

At steady state, a reversible refrigeration cycle discharges energy at the rate QH to a hot reservoir at temperature TH, while r

ludmilkaskok [199]

Answer:

a) $COP_{R} = 25.014$ , b) $T_{H} = 327.78\,K\,(54.63\,^{\textdegree}C)$

Explanation:

a) The coefficient of performance of a reversible refrigeration cycle is:

$COP_{R} = \frac{T_{L}}{T_{H}-T_{L}}$

Temperatures must be written on absolute scales (Kelvin for SI units, Rankine for Imperial units)

$COP_{R} = \frac{275.15\,K}{286.15\,K-275.15\,K}$

$COP_{R} = 25.014$

b) The respective coefficient of performance is determined:

$COP_{R} = \frac{Q_{L}}{Q_{H}-Q_{L}}$

$COP_{R} = \frac{8.75\,kW}{10.5\,kW-8.75\,kW}$

$COP_{R} = 5$

But:

$COP_{R} = \frac{T_{L}}{T_{H}-T_{L}}$

The temperature at hot reservoir is found with some algebraic help:

$COP_{R} \cdot (T_{H}-T_{L})=T_{L}$

$T_{H}-T_{L} = \frac{T_{L}}{COP_{R}}$

$T_{H} = T_{L}\cdot \left(1+\frac{1}{COP_{R}} \right)$

$T_{H} = 273.15\,K \cdot \left(1+\frac{1}{5} \right)$

$T_{H} = 327.78\,K\,(54.63\,^{\textdegree}C)$

8 0

3 years ago

Read 2 more answers