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kondor19780726 [428]
3 years ago
5

A heavy truck and a small truck roll down a hill. Neglecting friction, at the bottom of the hill the heavy truck has greater

Physics
1 answer:
postnew [5]3 years ago
3 0

Answer:

kenetic energy

Explanation:

or potential energy

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A particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point
seropon [69]

since centripetal acceleration is always towards the center of the circle

so at the given position where speed and acceleration is given the center coordinate will be towards the center of circle

also we know that

a_c = \frac{v^2}{r}

11.6 = \frac{2.5^2}{R}

R = 0.54 m

so the coordinates of the center will be

(x, y) = (3.20 , (3.5 + 0.54))

(x, y) = (3.20, 4.04)

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Ngle of a block is 45 degrees. What is the refractive index​
lyudmila [28]
1.6 ??? I hope I’m right
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The traditional view of mangrove forests as wastelands and unhealthy environments helped promote their degradation because _____
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Raditionally mangrove forests<span> were viewed as </span>wastelands and unhealthy environments<span>. People therefore reasoned that </span>their<span> removal would improve the health ...</span>
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3 years ago
Which of these factors will increase the speed of a sound wave in air?
Artemon [7]
<h3>Answer;</h3>

-Temperature

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3 years ago
A child whirls a 3.00 kg ball on a string .50 m from the axis of rotation in a horizontal circle. The ball makes 1 revolution in
melamori03 [73]

Answers:

a) 0.5 m/s^{2}

b) 1.5 N

Explanation:

a) The centripetal acceleration a_{c} of an object moving in a uniform circular motion is given by the following equation:  

a_{c}=\omega^{2} r  

Where:

\omega=1 \frac{rev}{s} is the angular velocity of the ball

r=0.5 m is the radius of the circular motion, which is equal to the length of the string

Then:

a_{c}=(1 \frac{rev}{s})^{2} 0.5 m  

a_{c}=0.5 m/s^{2} This is the centripetal acceleration of the ball

b) On the other hand, in this circular motion there is a force (centripetal force F) that is directed towards the center and is equal to the tension (T) in the string:

F=T=m. a_{c}

Where m=3 kg is the mass of the ball

Hence:

T=(3 kg)(0.5 m/s^{2})

T=1.5 N This is the tension in the string

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