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svlad2 [7]
3 years ago
8

is a constant related to the size and composition of the ball as well as the viscosity of the syrup. Find the rate at which grav

itational energy is converted to thermal energy once the ball reaches terminal velocity.
Physics
1 answer:
Neporo4naja [7]3 years ago
4 0

Answer:

Thermal = 0.48 W

Explanation:

Given:

- The complete question is:

" Starting from rest, a 0.0367-kilogram steel ball sinks into a vat of corn syrup. The thick syrup exerts a viscous drag force that is proportional to the ball's velocity: where C = 0.270 N- s/m is a constant related to the size and composition of the ball as well as the viscosity of the syrup. Find the rate at which gravitational energy is converted to thermal energy once the ball reaches terminal velocity. After the ball reaches terminal velocity its kinetic energy is constant Any further work done by gravity is therefore directly transferred to the syrup and ball as thermal energy The rate at which the energy is converted is the power supplied by gravity: where F is the force, v is the speed of the ball and B is the relative angle between the force and velocity vectors. The terminal velocity of the ball can be determined from the given information using Newton's Laws. "

Solution:

- Once the terminal velocity Vt of the body is reached, it begins to move downward  at constant speed. The drag force Fd then attains a constant value:

                                         Fd = - C • Vt

- Instant the rate of conversion of gravitational potential energy to thermal  energy becomes equal to the power dissipated by the drag force at the terminal  velocity is given by:

                                        Fd • Vt = - C • Vt ²

- To get the general velocity V , solve the equation of motion:

                                        mv' = -m*g - C*V

                                        v' = -g - [C/ m] * V

Where,

                                        v' = dv / dt

                                        dv / dt =  -g - [C/ m] * V

- We will denote [C/ m]  as constant B:

                                        dv / dt =  -B*[ g/B +  V ]

- Separate variables:

                                        dv / [ g/B +  V ]  =  -B*dt

- Integrate both sides:

                                        Ln | g/B +  V | = -B*t + C

                                        g/B +  V = C*e^( -B*t )

                                        V = C*e^( -B*t ) - g/B

- The above expression for velocity gives the velocity of the steel ball at any time t. We know that terminal velocity Vt is achieved when t - > ∞. Then we have:

                                       Vt = 0 - g/B = -m*g/C

- Then from power equation we have:

                                        P = - C*Vt^2

                                        P = -C ( -m*g/C )^2

                                        P = -(mg)^2 / C

                                        P = -(0.0367*9.81)^2 / 0.27

                                        P = - 0.48 W

- The rate at which gravitational energy is lost to surrounding gives rise to thermal energy of surrounding fluid Thermal = 0.48 W .

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Due to motion of the bar, there will be a constant change in flux and due to  Lenz's Law a current within the coil will be induced . This induced current can be used to power the light bulb.

As we know that the greater the speed, the greater the magnitude of the current, and the current is zero when there is no motion.

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7 0
11 months ago
An airplane pilot wishes to fly directly westward. According to the weather bureau, a wind of 75.0km/hour is blowing southward.
qaws [65]

Answer:

a)  correct answer is C , b) 14º  from the west to the north, c)   v_{1g} = 300.79 km / h

Explanation:

This is a relative speed exercise using the addition of speeds.

1) when it is not specified regarding what is being measured, the medicine is carried out with respect to the Z Earth, therefore the correct answer is C

2 and 3) In this case we must compose the speed using the Pythagorean Theorem.

     v_{1a}² = v_{1g}² + v_{ag}²

where v_{1a} is the speed of the airplane with respect to the air, v_{1g} airplane speed with respect to the Earth, v_{ag} air speed with respect to the Earth

in this case let's clear the speed of the airplane with respect to the Earth

  v_{1g} = √(v_{1a}² - v_{ag}²)

 v_{1g} = √ (310² - 75²)

 v_{1g} = 300.79 km / h

we find the direction of the airplane using trigonometry

   sin θ = v_{ag} / v_{1a}

   θ = sin⁻¹ (v_{ag} /v_{1a})

   θ = sin⁻¹ (75/310)

   θ= 14º

the pilot must direct the aircraft at an angle of 14º from the west to the north

7 0
3 years ago
What is the independent variable and dependent variable if the question is How much weight can you add to a boat before it sinks
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The independent variable is how much weight you add to the boat.

The dependent variable is: Did it or did it not sink yet ?


6 0
3 years ago
Water is being boiled in an open kettle that has a 0.52-cm-thick circular aluminum bottom with a radius of 12.0 cm. If the water
tangare [24]

Answer:

T_b=107.3784\ ^{\circ}C

Explanation:

Given:

  • thickness of the base of the kettle, dx=0.52\ cm=5.2\times 10^{-3}\ m
  • radius of the base of the kettle, r=0.12\ m
  • temperature of the top surface of the kettle base, T_t=100^{\circ}C
  • rate of heat transfer through the kettle to boil water, \dot Q=0.409\ kg.min^{-1}
  • We have the latent heat vaporization of water, L=2260\times 10^3\ J.kg^{-1}
  • and thermal conductivity of aluminium, k=240\ W.m^{-1}.K^{-1}

<u>So, the heat rate:</u>

\dot Q=\frac{0.409\times 2260000}{60}

\dot Q=15405.67\ W

<u>From the Fourier's law of conduction we have:</u>

\dot Q=k.A.\frac{dT}{dx}

\dot Q=k\times \pi.r^2\times \frac{T_b-T_t}{5.2\times 10^{-3}}

where:

A= area of the surface through which conduction occurs

T_b= temperature of the bottom surface

15405.67=240\times \pi\times 0.12^2\times \frac{T_b-100}{5.2\times 10^{-3}}

T_b=107.3784\ ^{\circ}C is the temperature of the bottom of the base surface of the kettle.

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3 years ago
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Whitepunk [10]
The answer I believe is c
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