No idea mate sorry, but i am just a highschool sophmore so chem isnt exactly in my repituar
I do not see a chart but I would say for what ever has been there the longest and what had more ability to withstand their environment ;) hope I helped
no of moles in 4 grams of H2=4/2=2
2H2+O2............2H2O
the reaction shows that 2 moles of H2 react with 1 mole of O2 to produced 2 moles H2O
now no of moles in 36grams of H2O=36/18=2
therefore he needed 1 mole of O2 to produce 36 grams of H2O and 1 mole of oxygen is equal to 32 grams of O2
Answer:
153.6771 amu
Explanation:
From the question given above, the following data were:
Isotope A:
Mass of A = 114.3789 amu
Abundance (A%) = 64.23%
Isotope B:
Mass of B =.?
Abundance (B%) = 100 – A%
Abundance (B%) = 100 – 64.23
Abundance (B%) = 35.77%
average atomic mass of Element Y = 128.4359 amu
The mass of the 2nd isotope (i.e isotope B) can be obtained as follow:
Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
128.4359 = [(114.3789 × 64.23)/100] + [(Mass of B × 35.77) /100]
128.4359 = 73.4656 + (Mass of B × 0.3577)
Collect like terms
128.4359 – 73.4656 = Mass of B × 0.3577
54.9703 = Mass of B × 0.3577
Divide both side by 0.3577
Mass of B = 54.9703 / 0.3577
Mass of B = 153.6771 amu
Therefore, the mass of the 2nd isotope is 153.6771 amu