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3 years ago

Which of the following statements accurately describes the properties of gases?

Physics

2 answers:

alexira [117]3 years ago

6 0

THE CORRECT ANSWER IS B

Ray Of Light [21]3 years ago

4 0

<span>A change in the pressure of a gas results in a more significant change in volume than it would in a liquid. is the statement that accurately describes the property of gas. Gas only depends on how you store it. the bigger the space the wider gas can expand, the smaller the space, the more compress the gas can become.</span>

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when two resistors are wired in series with a 12 v battery, the current through the battery is 0.31 a. when they are wired in pa

liberstina [14]

Let R₁ and R₂ be the two Resistance

R₁ - Resistance of 1st resistor

R₂ - Resistance of 2nd resistor

V = Voltage = 12V

I = O.31A ( in series)

I = 1.6 A ( in parallel)

when two resistance connected in series

Rs = R₁ + R₂

V = IRs = 12 /0.31 V

R₁+R₂ = 38.700Ω (equation1.)

When two resistance connected in parallel

$R_{p} =\frac { R_{1} R_{2}}{R_{1} + R_{2} }$

V = I Rp

V= I (R₂ R₁ /R₁ +R₂)

R₁ R₂ = 290.25 Ω

As we know

(R₁ - R₂ ) ² = (R₁ + R₂ ) ² - 4R1R2

Using above values we get,

(R₁ - R₂ ) ² = (38.70) ² - 4x 290.25

(R₁ - R₂ ) ² = 336.69 Ω

R₁ - R₂ = 18.34 (equation 2 )

Using equation 1 and 2 we get

R₁+ R₂ = 38.70 52

R₁ - R₂ = 18.34

R₁ = 28.535 Ω

Using the value of R₁ in equation 1 we get

R₂ = 38·700 - 28.535

RR₂ = 10.125 Ω

R₁ = 28. 535 v and R₂ 10.125 Ω

To know more about resistance in series and parallel:

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7 0

1 year ago

During maneuvers preceding the Battle of Jutland, the British battle cruiser Lion moved as follows (in nautical miles): 1.2 mile

lana66690 [7]

Answer:

total distance is 11.3 miles

Explanation:

Given data:

distance to north = 1.2 miles

distance to south at 38 degree east of south = 6.1 miles

distance to east of north at angle 89 degree = 4 miles

distance to east of north at angle 31 degree = 6.5 miles

considering each displacement as vector so we have

$\begin{pmatrix}0.0\\ 1.2\end {pmatrix} + \begin {pmatrix}3.8\\ -4.8\end{pmatrix} +\begin{pmatrix}4.0\\ 0.1\end {pmatrix}+\begin{pmatrix}3.3\\ 5.6\end{pmatrix} = \begin{pmatrix}11.1\\ 2.1\end{pmatrix}$