Two equipotential surfaces surround a +3.10 x 10-8-c point charge. how far is the 290-v surface from the 41.0-v surface?
1 answer:
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Answer:
d' = d /2
Explanation:
Given that
Distance = d
Voltage =V
We know that energy in capacitor given as
If energy become double U' = 2 U then d'
2 d ' = d
d' = d /2
So the distance between plates will be half on initial distance.
Answer:
It takes the train 7.5 seconds to reach top speed
The train travels 112.5 meters before it reaches its top speed
Explanation:
The Metro Rail makes a stop at NRG Stadium to pick up some Texans
fans after the game
After all the passengers board, the train accelerates at a rate of 4 m/s²
to a top speed of 30 m/s
We need to find the train takes how many seconds to reach the
top speed
Given is:
→ The train start from rest, then its initial speed u = 0
→ It acceleration a = 4 m/s²
→ Its top speed v = 30 m/s
To find the time we can use this rule;
→
→ seconds
<em>It takes the train 7.5 seconds to reach top speed</em>
<em></em>
Now we need to find how far the train travels before reaches top speed
We can use this rule;
→ v² = u² + 2as, where s is the distance
→ v = 30 m/s , u = 0 , a = 4 m/s²
Substitute these values in the rule
→ (30)² = 0 + 2(4) s
→ 900 = 8 s
Divide both sides by 8
→ s = 112.5 m
<em>The train travels 112.5 meters before it reaches its top speed </em>