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3 years ago

Two equipotential surfaces surround a +3.10 x 10-8-c point charge. how far is the 290-v surface from the 41.0-v surface?

1 answer:

8 0

T<span>he equation to be used here to determine the distance between two equipotential points is:
V = k * Q / r

where v is the voltage of the point, k is a constant, Q is charge of the point measured in coloumbs and r is the distance.
In this case, we can use ratio of proportions to determine the distance between the two points. in this respect,

Point 1:
V = k * Q / r = 290
r = k*Q/290 ; kQ = 290r

Point 2:
V = k * Q / R = 41
R = k*Q/41
from equation 10 kQ = 290r
R = 290/(41)= 7.07 m
The distance between the two points then is equal to 7.07 m.

</span>

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The instantaneous speed of a particle moving along one straight line is v(t) = ate−6t, where the speed v is measured in meters p

beks73 [17]

Answer:

v_max = (1/6)e^-1 a

Explanation:

You have the following equation for the instantaneous speed of a particle:

$v(t)=ate^{-6t}$ (1)

To find the expression for the maximum speed in terms of the acceleration "a", you first derivative v(t) respect to time t:

$\frac{dv(t)}{dt}=\frac{d}{dt}[ate^{-6t}]=a[(1)e^{-6t}+t(e^{-6t}(-6))]$ (2)

where you have use the derivative of a product.

Next, you equal the expression (2) to zero in order to calculate t:

$a[(1)e^{-6t}-6te^{-6t}]=0\\\\1-6t=0\\\\t=\frac{1}{6}$

For t = 1/6 you obtain the maximum speed.

Then, you replace that value of t in the expression (1):

$v_{max}=a(\frac{1}{6})e^{-6(\frac{1}{6})}=\frac{e^{-1}}{6}a$

hence, the maximum speed is v_max = ((1/6)e^-1)a

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3 years ago

g Design an experiment you can use to determine the mass of the metal cylinder. When you explain your experiment, be sure to men

kumpel [21]

Answer:

m = $\frac{k}{g}$ x,

graph of x vs m

Explanation:

For this exercise, the simplest way to determine the mass of the cylinder is to take a spring and hang the mass, measure how much the spring has stretched and calculate the mass, using the translational equilibrium equation

F_e -W = 0

k x = m g

m = $\frac{k}{g}$ x

We are assuming that you know the constant k of the spring, if it is not known you must carry out a previous step, calibrate the spring, for this a series of known masses are taken and hung by measuring the elongation (x) from the equilibrium position, with these data a graph of x vs m is made to serve as a spring calibration.

In the latter case, the elongation measured with the cylinder is found on the graph and the corresponding ordinate is the mass

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3 years ago

The substances in the table are combined, and Substance 1 loses 40 calories of heat. How many calories of heat will Substance 2

Luda [366]

Over time, the substances will reach equilibrium, meaning the heat calories lost by Substance 1 will be gained by Substance 2. Therefore, Substance 2 will eventually gain 40 calories of heat.

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3 years ago

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A Fourier analysis of the instantaneous value of a waveform can be represented by:

Viefleur [7K]

Answer:

t = 1

Explanation:

you dont know the value of the variable

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3 years ago

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In how many ways can the elements of [n] be permuted if 1 must precede 2 and 3 is to precede 4?

sp2606 [1]

No. of ways in the elements of n be permuted is n!/4

Number of elements = n

Number of face in which the element of n be permuted if 1 must proceed 2 and 3 is to precede 4.

n = 4

The possible permutation will

(1,2,3,4), (1,3,2,4),(1,3,4,2),(3,4,1,2),(3,1,2,4),(3,1,4,2)

There are 6 possible outcomes

For n= 5

With 1,2,3,4 we add 5 in the arrangement with above terms

The possible number of permutation

5×6 = 30

When n = 6

30×6 = 180.

So for an element

If 1 precede 2 and 3 is yo precede 4 is

= n! ×6/4!

= n!/4

No. of ways in the elements of n be permuted is n!/4

To know more about permutation:

brainly.com/question/4416319

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2 years ago