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3 years ago

The format specifier ________ is a placeholder for an int value. %d %n %int %s

1 answer:

8 0

%d is a format specifier that is a placeholder for an int value. It tells the compiler that we want to print an integer value that is present in variable a. In this way there are several format specifiers in c.

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a block measuring 20cm by 10cm by 5cm rests on a flat surface. The block has a weight of 3N. Determine the maximum pressure it e

Lady_Fox [76]

Max preassure = force / min area
= 3N / 0.1 x 0.05
= 600N/m(squared)
Copy off of the picture below itll help better, its what someone sent me when i asked this question

4 0

4 years ago

Difference between boyles law, charles law, and gay-lussacs law

lesya [120]

Answer:

All these laws give the relationship between two quantities of the gas among V (volume), p (pressure) and T (temperature), keeping the third one constant - however the two quantities change for each law

Explanation:

Calling:

p = gas pressure

V = gas volume

T = gas temperature (in Kelvin)

We have:

- Boyle's law: the pressure and the volume of a gas kept at constant temperature are inversely proportional. Mathematically,

$pV=const.$

- Charles's law: the temperature and the volume of a gas kept at constant pressure are directly proportional. Mathematically,

$\frac{V}{T}=const.$

- Gay Lussac's law: the temperature and the pressure of a gas kept at constant volume are directly proportional. Mathematically,

$\frac{p}{T}=const.$

3 0

3 years ago

Ask Your Teacher A trough is 16 ft long and its ends have the shape of isosceles triangles that are 2 ft across at the top and h

zloy xaker [14]

Answer:0.210 ft/min

Explanation:

Given

Length of trough $L=16 ft$

width of base $b=2 ft$

height of triangle $h=1 ft$

From Similar triangles property

$\frac{4}{2x}=\frac{1}{y}$

$2y=x$

volume of water in time t

$V=\frac{1}{2}\times (2x\cdot y)\cdot$

$V=16xy$

$V=32y^2$

differentiating

$\frac{\mathrm{d} V}{\mathrm{d} t}=32\times 2\times y\times \frac{\mathrm{d} y}{\mathrm{d} t}$

at $y=8 in.\approx 0.667 ft$

$9=64\times 0.667\times \frac{\mathrm{d} y}{\mathrm{d} t}$

$\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{9}{64\times 0.667}$

$\frac{\mathrm{d} y}{\mathrm{d} t}=0.210 ft/min$

6 0

4 years ago

A wave has a wavelength of 0.02m and period of 8.0*10^-2 seconds. calculate it's speed. (showing working)

erik [133]

Answer:

$v = 0.25m/s$

Explanation:

Given

$\lambda = 0.02m$ --- Wavelength

$T = 8.0 * 10^{-2}s$ --- Period

Required

Determine the velocity of the wave

This is calculated using:

$v = \frac{\lambda}{T}$

$v = \frac{0.02m}{8.0*10^{-2}s}$

$v = \frac{0.02m}{8.0*0.01s}$

$v = \frac{0.02m}{0.08s}$

$v = 0.25m/s$

<em>Hence, the velocity is 0.25m/s</em>

4 0

3 years ago

Harmonics problem. A square wave of frequency f contains harmonics (sine waves) at f, 3f, 5f, 7f, ... . Suppose a system respond

ad-work [718]

Answer:

Explanation:

If the fundamental frequency of the square wave is 10 Khz, and contains harmonics at f, 3f, 5f, etc., it will have a component at 10 Khz, other at 30 Khz, and another one at 50 Khz.
If the system responds to frequencies in the range between 20 Khz and 40 KHz only, the shape of the response will contain only a 30 Khz sine wave (3rd harmonic of 10 Khz).

4 0

3 years ago