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Kisachek [45]
3 years ago
7

Which of the following statements is correct regarding the speed and velocity of an object? A. An object’s speed is determined b

y the distance the object traveled and how long it took the object to travel that distance. B. An object’s velocity is determined by the distance the object traveled, how long it took the object to travel that distance and what acceleration the object traveled. C. An object’s velocity is determined by the distance the object traveled and how long it took the object to travel that distance. D. An object’s speed is determined by the distance the object traveled, how long it took the object to travel that distance and what direction the object traveled.
Chemistry
1 answer:
Natalija [7]3 years ago
4 0

Answer:

Explanation:

D

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Why the mixture of bromine and ethane is discoloured when left in the sun​
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Answer:

In the presence of UV light, ethane will react with bromine in a substitution reaction. UV light is the condition under which the reaction will occur so it is written above the arrow in the chemical equation. As the reaction proceeds, the intensity of the re-brown colour of the bromine water decreases.

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How many carbon atoms are present in 0.46 moles of C2H6O?
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3 0
3 years ago
Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant o
sattari [20]

Answer:

4.26 %

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant of nitrous acid is  4.50  ×  10 ⁻⁴.</em>

<em />

Step 1: Given data

Initial concentration of the acid (Ca): 0.249 M

Acid dissociation constant (Ka): 4.50  ×  10 ⁻⁴

Step 2: Write the ionization reaction for nitrous acid

HNO₂(aq) ⇒ H⁺(aq) + NO₂⁻(aq)

Step 3: Calculate the concentration of nitrite in the equilibrium ([A⁻])

We will use the following expression.

[A^{-} ] = \sqrt{Ca \times Ka } = \sqrt{0.249 \times 4.50 \times 10^{-4}  } = 0.0106 M

Step 4: Calculate the percent ionization of nitrous acid

We will use the following expression.

\alpha = \frac{[A^{-} ]}{[HA]} \times 100\% = \frac{0.0106M}{0.249} \times 100\% = 4.26\%

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