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choli [55]
3 years ago
13

Example of false solutions and true solutions ​

Chemistry
1 answer:
horrorfan [7]3 years ago
5 0
False solutions are natural gas, nuclear power ‎ and industrial biomass incineration.

sugar in water is an example of true solution.
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Why is the chemical symbol for calcium ca
Assoli18 [71]
You are right, it's CA Calcium, 40.08, Group 2 and Row 4.
6 0
3 years ago
4. An 82 kg hiker climbs Mt. Humphrey near Flagstaff. During a two hour period, the hiker's
bazaltina [42]

Answer:

\Delta E = 434253.96\,J, \Delta P = 60.313\,W

Explanation:

The change in energy is given by the change in gravitational potential energy:

\Delta E = m\cdot g \cdot \Delta h

\Delta E = (82\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (540\,m)

\Delta E = 434253.96\,J

The average rate of change in terms of time is approximately this:

\Delta P = \frac{\Delta E}{\Delta t}

\Delta P = \frac{434253.96\,J}{(2\,h)\cdot (\frac{3600\,s}{1\,h} )}

\Delta P = 60.313\,W

8 0
3 years ago
Which part of the Periodic Table of the elements is used to identify valence electrons? *
irina1246 [14]
The number of valence electrons of an element can be determined by the periodic table group (vertical column) in which the element is categorized
6 0
2 years ago
Identify the name of the compound that goes with this chemical compound
postnew [5]
What is the chemical compound?
8 0
3 years ago
4. How many grams of hydrogen is produced from 12.5 g of Mg reacting with hydrochloric acid in this
Volgvan

From the reactions, 1.04 g of H2 and 7.995 g of aluminum phosphate is produced.

<h3>What is stoichiometry?</h3>

The term stoichiometry has to do with the amount of substances that participates in a reaction.

For reaction 1;

Mg + 2HCl → MgCl₂ + H₂

Number of moles of Mg reacted =  12.5 g/24g/mol = 0.52 moles

If 1 mole of Mg produced 1 mole of H2

0.52 moles produces 0.52 moles of H2

Mass of H2 =  0.52 moles * 2 g/mol = 1.04 g

For reaction 2;

2Li3PO4 + Al2(SO4)3 → 3Li2SO4 + 2AIPO4

Number of moles of lithium phosphate =  7.5 g/116 g/mol = 0.065 moles

2 moles of Li3PO4 produced 2 moles of AIPO4

0.065 moles of  Li3PO4 produced 0.065 moles of AIPO4

Mass of AIPO4  = 0.065 moles  * 123 g/mol = 7.995 g

Learn more about stoichiometry:brainly.com/question/9743981

#SPJ1

8 0
2 years ago
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