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choli [55]
3 years ago
13

Example of false solutions and true solutions ​

Chemistry
1 answer:
horrorfan [7]3 years ago
5 0
False solutions are natural gas, nuclear power ‎ and industrial biomass incineration.

sugar in water is an example of true solution.
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PLEASE HELP ASAP!!! science
Ksju [112]

Answer:

It's the oesophagus.

Explanation:

The worm digestive system consists of the pharynx, the esophagus, the crop, the intestine and the gizzard. The oesophagus is not mentioned. Thus, it's not part of the worm digestive system.

8 0
3 years ago
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Why do some elements (ex: Neon) have a large number of spectral lines, compared to Hydrogen?
Doss [256]
<span> The production of absorption and emission lines . The first theory of the atom to provide an explanation of </span>hydrogen's<span> observed </span>spectral lines<span>  those two energy levels, the electron </span>can<span> exist only in </span>certain<span> sharply defined . The </span>number<span> of protons in the nucleus of an atom determines the </span>element<span> that </span>
7 0
3 years ago
When you run an electrical current through liquid water, the water molecules are split apart to form oxygen and hydrogen gas. Th
Snezhnost [94]
The answer is "chemical properties". The original water is split apart by the current 
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<span>the original water is lost and new substances, H2 & O2, are produced. </span>
<span>Hope this answers your question.</span>
3 0
3 years ago
A 10.11 g sample of NaBr contains 22.34 % Na by mass. Considering the law of constant composition (definite proportions), how ma
Ksenya-84 [330]

Answer:

1.58\ \text{g}

Explanation:

10.11 g sample of NaBr contains 22.34% Na by mass

According to the law of constant composition the if one sample of NaBr has 22.34% of Na by mass then any other sample of NaBr will have the same percentage of the amount of Na.

For a sample of 7.09 g we have

7.09\times \dfrac{22.34}{100}=1.583906\approx 1.58\ \text{g}

The mass of sodium in the required sample is 1.58\ \text{g}.

8 0
3 years ago
Draw the major organic product in the reaction scheme. Be sure to clearly show stereochemistry (if applicable). The starting mat
never [62]

Answer:

See answer below

Explanation:

The picture below will show you the final product and mechanism.

In the first step, the NaNH₂ is a strong base, so, this base will substract the hydrogen from carbon 2, to generate a negative charge there, and then, carbon 2 becomes a nucleophyle.

As a nucleophyle it will attack to the CH₃I in the next step, and it will attach to the CH₃.

The second step is just a regular step to reduce the triple bond of the alkyne to alkane or alkene, this will depend on the quantity of the reactant. In this case, an alkene.

Hope this helps,,,,,,k

5 0
3 years ago
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