<h3>
Answer:</h3>
3.03 × 10²⁵ formula units KCl
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Unit 0</u>
- Reading a Periodic Table
- Writing Compounds
<u>Atomic Structure</u>
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
50.3 mol KCl (Potassium chloride)
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
<u /> = 3.02907 × 10²⁵ formula units KCl
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
3.02907 × 10²⁵ formula units KCl ≈ 3.03 × 10²⁵ formula units KCl
To solve this, let's assume ideal gas behavior.
PV=nRT
Let's solve for n. Convert units to SI units first.
Pressure = 833 torr(101325 Pa/760 torr) = 111,057.53 Pa
Volume = 250 mL(1 L/1000 mL)(1 m³/1000 L) = 2.5×10⁻⁴ m³
Temperature = 42.4 + 273 = 315.4 K
n = (8,314 J/mol·K)(315.4 K)/(111057.53 Pa)(2.5×10⁻⁴ m³)
n = 94.45 mol
The molar mass of ammonia is 17.031 g/mol.
Mass = 94.45*17.031 = <em>1,608.51 g ammonia</em>
Answer:
C6H12O6 → 2C2H5OH + 2CO2
Explanation:
Glucose is an organic molecule, specifically a sugar, with the formula C612O6 while ethanol is another organic molecule with formula; C2H5OH.
However, as rightly said in this question, ethanol can be got from glucose via a process called fermentation in the presence of a catalyst called YEAST. The balanced equation is as follows:
C6H12O6 → 2C2H5OH + 2CO2
Actualy the answer is Lower pressure causes the papers to come closer together.
Please mark brainiest if this is correct and helpful.
Answer and explanation:
The relative rates of free radical halogenation is in the order of,
F₂ (10⁸) > Cl₂ (1) > Br₂ (10⁻¹¹) > I₂ (10⁻²²)
The above order also show a decreasing reactivity from left to right
Hence, reaction of fluorine with alkanes is highly reactive and it is too difficult to control.
The reaction with Cl₂ is moderately fast, while with Br₂ is slow and with I₂ is too slow reaches to equilibrium.
Hence in general we don't prefer radical fluorination of alkanes.