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nalin [4]
3 years ago
13

Make a list of five agriculture based occupation ​

Physics
2 answers:
yanalaym [24]3 years ago
6 0

They are;

  1. Agricultural Engineer
  2. Agricultural specialist
  3. Farm Manager
  4. Agricultural economist
  5. Commercial mixed farming
  6. Thank you hope it helps you. May god bless you❤
grandymaker [24]3 years ago
4 0

Answer:

Agricultural Engineer.

Agricultural Food Scientist.

Agricultural Inspector.

Agricultural Manager.

Agricultural Specialist.

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What is the likely identity of a metal if a sample has a mass of 63.5 g when measured in air and an apparent mass of 60.2 g when
Gre4nikov [31]

Answer:

Gold

Explanation:

Given:

Mass of sample = 63.5 g

Mass of water = 60.2 g

Find:

Object

Computation:

Mass of water displaced = 63.5 g - 60.2 g

Mass of water displaced = 3.3 g

So, volume in water = 3.3 cm³

Density = Mass / Volume

Density = 63.5 g / 3.3

Density = 19.24

So,

Object ,must be gold.

7 0
3 years ago
Susan is running to the right, in the +x-direction, at 2 m/s. A bird flies past her, traveling to the left at 10 m/s. What is th
anastassius [24]

The concept of relative velocity can be found the speed of the bird respecting susan v = -12 m / s. The negative sign indicates that the bird is approaching susan

given parameter

  • the speeds of Susam and the bird

to find

  • the relative speed between Susan and the bird

Velocity is a vector unit, therefore, in addition to magnitude, it has direction and sense, therefore, to make the sum of the same quantities, vector relations must be used

         v₁ = v₂ + v₃

where v₁, v₂ and v₃ are velocity and the bold letters indicate vectors

in this case Susan and the bird go on the x axis therefore the algebra is reduced to the algebraic sum. We will assume that the positive direction is to the right of the x-axis, consequently the velocities are:

Susan       v_{st} = 2 m / s

Bird          v_{bt} = - 10 m / s

The relative velocity is the vector sum of the velocities of the bodies, one way to perform this sum is by using subscripts

           v_{pt} =   v_{ps} + v_{st}

           

Where  v_{ps} is the speed of the bird relative to susan, v_{st} is the speed of susan relative to the ground, and v_{pt} is the speed of the bird relative to the ground.

            v_{ps} = v_{pt} - v_{st}

            v_{ps} = -10 - 2

            v_{ps} = - 12 m / s

Using the concept of relative velocity, the velocity of the bird respecting susan v = -12 m/s can be found. The negative sign indicates that the bird is approaching susab.

Learn more about relative velocity here:

brainly.com/question/19260269

5 0
3 years ago
Which of the following best describes this image?
katrin [286]

Answer:

high accuracy low precision.

Explanation:

7 0
3 years ago
A woman (mass= 50.5 kg) jumps off of the ground, and comes back down to the ground at a velocity of -8.4 m/s.
Blizzard [7]

Answer:

Approximately 1.6\times 10^{3}\; \rm N.

Explanation:

By the Impulse-Momentum Theorem, the change in this woman's momentum  will be equal to the impulse that is applied to her.

The momentum p of an object is equal to the product of its mass m and velocity v. That is: p = m \cdot v.

Let v(\text{before}) and v(\text{after}) represent the velocity of the woman before and after the landing. Let m represent the woman's mass.

  • The woman's momentum before the landing would be m \cdot v(\text{before}).
  • The woman's momentum after the landing would be m \cdot v(\text{after}).

Therefore, the change in this woman's momentum would be:

\begin{aligned}& \Delta p \\ & = p(\text{after}) - p(\text{before}) \\ &= m \cdot (v(\text{after})- v(\text{before}))\end{aligned}.

On the other hand, impulse is equal to force multiplied by the duration of the force. Let F represent the average force on the woman. The impulse on her during the landing would be F \cdot t.

Apply the Impulse-Momentum Theorem.

  • Impulse: F\cdot t.
  • Change in momentum: m \cdot (v(\text{after})- v(\text{before})).

Impulse is equal to the change in momentum:

F \cdot t = m \cdot (v(\text{after})- v(\text{before})).

After landing, the woman comes to a stop. Her velocity would become zero. Therefore, v(\text{after}) = 0\; \rm m \cdot s^{-1}.

\begin{aligned}F &= \displaystyle \frac{m \cdot (v(\text{after})- v(\text{before}))}{t} \\ &= \frac{50.5\; \text{kg} \times \left(0 \; \mathrm{m \cdot s^{-1}}- 8.4\; \mathrm{m \cdot s^{-1}}\right)}{0.27\; \rm s} \\ &\approx 1.6 \times 10^{3}\; \rm N\end{aligned}.

3 0
4 years ago
When an electron in a certain excited energy level in a one-dimensional box of length 2.00 Å makes a transition to the ground st
Fiesta28 [93]

Answer:

Calculate the wavelength associated with an electron with energy 2000 eV.

Sol: E = 2000 eV = 2000 × 1.6 × 10–19 J

5 0
3 years ago
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