2. A string with a length of 0.9m that is fixed at both ends
1 answer:
Answer:
2a.) Wavelength = 1.8 m
2b.) F = 66.67 Hz
3a.) Find the attached file
3b.) Wavelength = 0.6 m
Explanation:
Given that the
Length L = 0.9m
Wavelength (λ) = 2L/n
Where n = number of harmonic
If n = 1, then
Wavelength (λ) = 2L = 2 × 0.9 = 1.8 m
b.)
If waves travel at a speed of 120m/s on this string, what is the frequency
associated with the longest wave (first harmonic)?
Given that V = 120 m/s
V = Fλ
But λ = 2L, therefore,
F = V/2L
F = 120/1.8
F = 66.67 Hz
3. b.) If there are two node, the position will be in 3rd position which is 3rd harmonic
Using the same formula,
Wavelength (λ) = 2L/n
Where n = 3
Wavelength (λ) = 2 × 0.9/3
Wavelength (λ) = 0.6 m
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Answer:
x = 54.15 meters between the balloons horizontally.
Explanation:
Hence, vertical distance between balloons is 12.8 meters.
y= 61-48.2 = 12.2 m
A right-angle triangle is formed with,
angle θ = 13.3 degrees
opposite (y) = 12.8
adjacent (x) = ?
Now by putting the values in the above equation.
x = 54.15 meters between the balloons horizontally.
