Answer:
The graphs of the two function will not intersect.
Step-by-step explanation:
We are given a quadratic function f(x).
Also g(x) is given by a set of values as:
x g(x)
1 -1
2 0
3 1
As g(x) is a linear function hence we find out the equation of g(x) by the slope intercept form of a line: y=mx+c
let g(x)=y
when x=1 , g(x)=-1
-1=m+c----(1)
when x=2 , g(x)=0
0=2m+c------(2)
Hence, on solving (1) and (2) by method of elimination we get:
m=1 and c=-2
Hence, the equation of g(x) is:
g(x)=x-2
So clearly from the graph we could see that the graph of the two functions will never intersect.
2x - 3y = 3.....multiply by 4
5x - 4y = 4....multiply by -3
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8x - 12y = 12 (result of multiplying by 4)
-15x + 12y = -12 (result of multiplying by -3)
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- 7x = 0
x = 0 <===
Answer:
Step-by-step explanation:
We are given that a function
We have to find the average value of function on the given interval [1,e]
Average value of function on interval [a,b] is given by
Using the formula
By Parts integration formula
u=ln x and v=dx
Apply by parts integration
![f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))](https://tex.z-dn.net/?f=f_%7Bavg%7D%3D%5Cfrac%7B1%7D%7Be-1%7D%28%5Bxlnx%5D%5E%7Be%7D_%7B1%7D-%5Cint_%7B1%7D%5E%7Be%7D%28%5Cfrac%7B1%7D%7Bx%7D%5Ctimes%20xdx%29%29)
![f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})](https://tex.z-dn.net/?f=f_%7Bavg%7D%3D%5Cfrac%7B1%7D%7Be-1%7D%28elne-ln1-%5Bx%5D%5E%7Be%7D_%7B1%7D%29)
By using property lne=1,ln 1=0
Answer:
56.4 ft
Step-by-step explanation:
The tangent of the angle relates the opposite side (height above the window) to the adjacent side (distance between buildings) in the right triangle that models this geometry.
Tan = Opposite/Adjacent
tan(35°) = (height above window)/(distance between buildings)
height above window = (52 ft)tan(35°) ≈ 36.4 ft
Added to the window height of 20 ft, the height of the other building is ...
20 ft + 36.4 ft = 56.4 ft
|dw:1375141940415:dw|
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the answer would be
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29^2
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(dont forget the square root )
29²
