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DIA [1.3K]
3 years ago
12

The student uses 25.0cm3 of 1.60mol/dm3 sodium hydroxide to prepare the crystals.

Chemistry
1 answer:
o-na [289]3 years ago
5 0
First you have to calculate how many mols of NaOH are in the 25.0 cm3. As one dm3 is equal to 10cm*10cm*10cm=1000 cm3, there are 0.0016 mol/cm3 and therefore 25cm3*0.0016 mol/cm3=0.04 mol NaOH. 
According to the stochiometrics of the reaction a maximum yield of 0.5*0.04=0.02 mol Na2SO4 can be formed. Multiplying by the molar mass gives the mass: 0.02mol*142.04g/mol=2.84 g 
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