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julia-pushkina [17]
2 years ago
11

Drag the numbers to order them from greatest to least, with the greatest at the top.

Mathematics
1 answer:
astraxan [27]2 years ago
4 0

Step-by-step explanation:

5.03709

4.923935

√17

√12

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DO THE MATH
lesantik [10]

f(p) where p is the price in thousands. f(250) means the average number of days before being sold for $250,000. Lets take a look at the answers and see which fits the best:

1. The house sold for $250,000. (This is what the 250 stands for, but we need to find what f(250) means and not just 250)

2. The house stayed on the market for an average of 250 days before being sold. (Nope, not even close)

3. This is the average number of days the house stayed on the market before being sold for $250,000. (Yes! This seems right, f(250) is the average number of days before being sold for $250,000)

4. The house sold on the market for $250,000 and stayed on the market for an average of 250 days before being sold. (Nope, we are not told anywhere that it takes 250 days to be sold)

This means that our answer has to be 3) This is the average number of days the house stayed on the market before being sold for $250,000.

I hope I've helped! :)

4 0
2 years ago
In a study conducted at a large long-term care facility, two data collectors examined 56 pressure ulcers on 40 different subject
lara31 [8.8K]

Answer:

Interrater reliability between the two data collectors was high

Step-by-step explanation:

Explanation-

  • Interrater reliability is the consistency of observations between two or more observers.
  • An Agreement of 54 out of 56 scores would indicate a high level of interrater reliability.
  • The data collection method was appropriate for pressure ulcer risk assessment.
  • The risk assessments did not have to be done by both evaluators at the same time.
5 0
2 years ago
How do I solve for -31 -8r = -3(5r -6)
Dennis_Churaev [7]
Our current equation is:
-8r -31 = -3(5r -6)
To solve for this, we need to get r on one side of the equation and then simplify if needed.
On the right side of the equation, we have a pending Distributive Property, which is when you multiply the number/variable outside of the parenthesis by all numbers/variables in the parenthesis.
Let's simplify this Distributive Property to help understand our equation better.
-3(5r -6)
Multiply -3 by each number/variable separately (unless they are already being multiplied, like 2x, 1/2x, etc).
-3(5r) + -3(-6).
-3(5r) = -15r
-3(-6) = 18 (both negatives need to be in parenthesis to keep a product as negative, and if you do not multiply them in that way, you will end up with a positive product).
Your equation now is:
-8r -31 = -15r + 18
Add 15r to both sides to get r on one side.
7r -31 = 18 is now our current equation.
Add 31 to both sides to get 7r by itself.
7r = 49 is now our equation.
r is still being multiplied by 7, so we need to do the opposite of multiplying by 7.
Divide both sides by 7.
r = 7.
I hope this helps!
8 0
3 years ago
What is the function rule for this question?
Lemur [1.5K]
To calculate the remaining number of teams, use the sequence formula:
a(n) = a(1)Rⁿ-¹
Where a(n) and a(1) are the nth and first terms. R is the factor. Therefore, 24 teams is valid value.
After 5 rounds :
a(5) = 128*(½)⁴
a(5) = 128/16 = 8

8 teams are remained.

6 0
3 years ago
For number 6, evaluate the definite integral.
maks197457 [2]
\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\

\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
\\\\\\
u(28)=8+2(28)\implies u(28)=64

\bf \\\\
-------------------------------\\\\
\displaystyle  \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
\\\\\\
\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2}  \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3
3 0
2 years ago
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