Answer:12 seconds
Explanation:the formula is s=d/t.
s= speed, d=distance, and t= time
Solve for t
Your new arranged formula is t=d/s
T=108/9
T= 12
Dii ok not forget your units
My answer would be B, Hope i helped u??
For this question we use Boyle's law which states the relationship between pressure and volume. At constant temperature, pressure of a gas is inversely proportional to volume of a gas.
PV = k
where P-pressure, V - volume and k - constant
Therefore P1V1 = P2V2
where parameters for 1st instance are on the left side and parameters for the 2nd instance are on the right side.
183 ml x 310 mmHg = 90.6 ml x P2
P2 = 183 x 310 / 90.6
= 626.16 mmHg
pressure required is 626.16 mmHg
Hello!
The substances, ordered according to their dissolving time in water, are the following
Sugar Cubes > Granulated Sugar > Powdered Sugar
The difference between these substances is the degree of order. According to collision theory, for a substance to be dissolved, successful collisions between solvent molecules and solute molecules need to happen. as molecules are more ordered, successful collisions are less likely to happen, because atoms are fixed into a crystalline structure.
When the molecule is less ordered, successful collisions are more likely to occur, as the atoms can be impacted from different sides and aren't fixed into a given position.
As the degree of order increases, the dissolving time in water will be higher too, as more time would be required for successful collisions to happen. The most ordered substance is sugar cubes, followed by granulated sugar and powdered sugar, and that order is the same as the order for dissolving time.
Have a nice day!
The change in enthalpy associated with the change in the water’s temperature is 1254 J.
<h3>What is specific heat?</h3>
The amount of heat required to increase the temperature of one gram of a substance by one Celsius degree is known as specific heat.
Enthalpy change will be calculated as:
ΔH = -cmΔT, where
m = mass of water = 50g
c = specific heat of water = 4.18J/g°C
ΔT = change in temperature = 28 - 22 = 6 °C
On putting values in the above equation, we get
ΔH = -(4.18)(50)(6) = -1254 J
Hence change in enthalpy of the reaction is -1254 J.
To know more about enthalpy change, visit the below link:
brainly.com/question/11628413
#SPJ1