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2 years ago

A sealed flask contains 3.82 x 1024 molecules of CO, How many moles of Co, are in the flask?

Chemistry

2 answers:

lesya [120]2 years ago

5 0

Answer:

if you meant 3.82* 10^24, the answer is 6.34551495 moles

if you meant 3.28*1024, the answer is 6.49780731*10^-21 moles

since you're going from molecules to moles, you need to divide by Avogadro's number which is 6.02*10^23

Lynna [10]2 years ago

4 0

Answer:

3.82 × 1024

= 3911.68

<h3>I hope this helps!</h3>

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3 years ago

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When 21.45 g of KNO3 was dissolved in water in a calorimeter, the temperature fell from 25.00°C to 14.14 °C. If the heat capacit

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25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)

<h3>Explanation</h3>

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$\text{KNO}_3\;(s) \to \text{KNO}_3\;(aq)$ .

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Relative atomic mass from a modern periodic table:

K: 39.098;
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O: 15.999.

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$M(\text{KNO}_3) = 39.098 + 14.007 + 3\times 15.999 = 101.102\;\text{g}\cdot\text{mol}^{-1}$ .

Number of moles of the process = Number of moles of $\text{KNO}_3$ dissolved:

$\displaystyle n = \frac{m}{M} = \frac{21.45}{101.102} = 0.212162\;\text{mol}$ .

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$Q = C\cdot \Delta T = 0.505 \times (25.00 - 14.14) = 5.4843\;\text{kJ}$ for $0.212162\;\text{mol}$ . By convention, the enthalpy change $\Delta H$ measures the energy change for each mole of a process.

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The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.

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2 years ago