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GalinKa [24]
3 years ago
10

What does the formula "F=m xa" mean?​

Physics
1 answer:
strojnjashka [21]3 years ago
5 0

Answer:

Force = Mass x Acceleration

Explanation:

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A wave along a guitar string has a frequency of 540 Hz and a wavelength of 4.3 m. Calculate the velocity of the wave.
Virty [35]

Answer:

Velocity of wave =  2322 m /sec

Explanation:

We know that, Velocity of wave v = n  λ

Given, n = 540 Hz,  λ=4.3 m , v = ?

Putting the value of n and λ

Velocity of wave = 540 x 4.3 = 2322 m /sec

8 0
3 years ago
Read 2 more answers
Power of sunlight on Earth The Sun emits about 3.9 * 1026 J of electromagnetic radiation each second. (a) Estimate the power tha
ratelena [41]

Answer:

a)6.34 x  10^{7}W/m²

b)1.37 x 10^{3 W/m²

c) see explanation.

Explanation:

a)The relation of intensity'I' of the radiation and area 'A' is given by:

I= P/A

where P= power of sunlight i.e 3.9 x 10^{26} J

and the area of the sun is given by,

A= 4πR_{sun} => 4π(\frac{1.4*10^{9} }{2} )^{2}

A=6.15 x 10^{18}m²

I_{sun} =  3.9 x 10^{26} / 6.15 x 10^{18} =><u> 6.34 x  </u>10^{7}<u>W/m²</u>

b) First determine the are of the sphere in order to determine intensity at the surface of the virtual space

A= 4πR

Now R= 1.5 x 10^{11m

A=  4π x 1.5 x 10^{11 =>2.83 x 10^{23 m²

The power that each square meter of Earths surface receives

I_{earth =   3.9 x 10^{26}/2.83 x 10^{23 =><u>1.37 x </u>10^{3<u> W/m²</u>

<u />

c) in part (b), by assuming the shape of the wavefront of the light emitted by the Sun is a spherical shape so each point has the same distance from the source i.e sun on the wavefront.

6 0
3 years ago
An irrigation canal has a rectangular cross section. At one point whare the canal is 16.0 m wide, and the water is 3.8 m deep, t
Irina-Kira [14]

Answer:

The depth of the water at this point is 0.938 m.

Explanation:

Given that,

At one point

Wide= 16.0 m

Deep = 3.8 m

Water flow = 2.8 cm/s

At a second point downstream

Width of canal = 16.5 m

Water flow = 11.0 cm/s

We need to calculate the depth

Using Bernoulli theorem

A_{1}V_{1}=A_{2}V_{2}

Put the value into the formula

16.0\times3.8\times2.8=16.5\times x\times 11.0

x=\dfrac{16.0\times3.8\times2.8}{16.5\times11.0}

x=0.938\ m

Hence,  The depth of the water at this point is 0.938 m.

7 0
4 years ago
Suppose you are visiting your uncle at an ocean boat club and you hear that a storm, with high winds, creating large waves is ap
Airida [17]
I would say wait no come back stay here where u will be protected
4 0
3 years ago
Consider the uniform electric field E = (8.0ĵ + 2.0 ) ✕ 103 N/C. What is its electric flux (in N · m2/C) through a circular area
cluponka [151]

Answer:

5.09 x 10⁵ Nm²/C

Explanation:

The electric flux φ through a planar area is defined as the electric field Ε times the component of the area Α perpendicular to the field. i.e

φ = E A

From the question;

E = (8.0j + 2.0k) ✕ 10³ N/C

r = radius of the circular area = 9.0m

A = area of a circle = π r²           [Take π = 3.142]

A = 3.142 x 9² = 254.502m²

Now, since the area lies in the x-y plane, only the z-component of the electric field is responsible for the electric flux through the circular area.

Therefore;

φ = (2.0) x 10³ x 254.502

φ = 5.09 x 10⁵ Nm²/C

The electric flux is 5.09 x 10⁵ Nm²/C

4 0
3 years ago
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