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garik1379 [7]
2 years ago
11

Describes the relationship between the spectrum of one atom and the spectrum of another?

Physics
1 answer:
krok68 [10]2 years ago
6 0

The relationship between the number of visible spectral lines are identical for atoms .However they have unique wavelengths.

Option B

<u> Explanation:</u>

A spectrum is a range of frequencies or a range of wavelengths. The photon energy of the emitted photon is equal to the difference between two states. For every atom there are quite many electron transitions and each has a energy difference.

This difference in wavelength causes spectrum .As each element emission spectrum is unique because each atom has different energy and causes uniqueness in the emission spectrum . Hence, due to the difference in energy it emits different wavelengths.

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4 identical coins of mass M and radius R are placed in a square, so the center of each coin lies on a corner of the square. The
kati45 [8]

Answer:

I_{total} = 10 M R²

Explanation:

The concept of moment of inertia in rotational motion is equivalent to the concept of inertial mass for linear motion. The moment of inertia is defined

     I = ∫ r² dm

For body with high symmetry it is tabulated, in these we can simulate them by a solid disk, with moment of inertia for an axis that stops at its center

       I = ½ M R²

As you hear they ask for the moment of energy with respect to an axis parallel to the axis of the disk, we can use the theorem of parallel axes

        I = I_{cm} + M D²

Where I_{cm} is the moment of inertia of the disk, M is the total mass of the system and D is the distance from the center of mass to the new axis

Let's apply these considerations to our problem

The moment of inertia of the four discs is

    I_{cm} = I

    I_{cm} = ½ M R²

     

For distance D, let's use the Pythagorean Theorem. As they indicate that the coins are touched the length of the square is L = 2R, the distance from any spine to the center of the block is

         D² = (R² + R²)

         D² = R² 2

Let's calculate the moment of inertia of a disk with respect to the axis that passes through the center of the square

     I = ½ M R2 + M R² 2

     I = 5/2 M R²

This is the moment of inertia of a disc as we have four discs and the moment of inertia is a scalar is additive, so

   I_{total} = 4 I

   I_{total} = 4 5/2 M R²

    I_{total} = 10 M R²

5 0
3 years ago
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