Answer:
Explanation:
velocity of ship with respect to water = 6.5 m/s due north

velocity of water with respect to earth = 1.5 m/s at 40° north of east

velocity of ship with respect to water = velocity of ship with respect to earth - velocity of water with respect to earth



The magnitude of the velocity of ship relative to earth is
= 5.66 m/s
If you were to sit a hot cup of water out side it would frezze faster
The second option is the correct one. m/s^2
Answer:
60
Explanation:
Every 60 minutes is an hour
The equation for percent error is
% Error =

Our experimental is 2.85g/cm^3 and the accepted is 2.7g/cm^3
Thus our % Error = 5.555%