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Anna35 [415]
3 years ago
13

Can you please help me

Mathematics
1 answer:
MariettaO [177]3 years ago
6 0

Answer:

you will add the numerator and the denominator and or you look for lowest common factor

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How can we simplify radicals involving negative values?
RSB [31]

Answer:

using imaginary numbers

Step-by-step explanation:

4 0
2 years ago
I need help number 14 and 15.
Veronika [31]
Go 2 openstudy hope that helped

 
5 0
2 years ago
The current average property value is two-sevenths more than last year’s average value. What was last year’s average property va
Ilya [14]

Answer:

63350

Step-by-step explanation:

Given that the current average property value is two-sevenths more than last year’s average value.

Let x be the last year's average property

Then we have as per the given information this year property value

=x+\frac{2}{7} x

Equate this to

x+\frac{2}{7} x=81450\\9x = 7(81450)\\x = 7(9050)\\x= 63350

6 0
3 years ago
Student performance across discussion sections: A professor who teaches a large introductory statistics class (197 students) wit
adell [148]

Answer:

The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.

Step-by-step explanation:

Assumptions:

1. The sampling from the different discussion sections was independent and random.

2. The populations are normal with means and constant variance

H_0: There's no variation among the discussion sections

H_1: There's variation among the discussion sections

\alpha =0.05

                Df     Sum Sq       Mean sq    F value     Pr(>F)

Section     7       525.01         75             1.87            0.99986

Residuals  189    7584.11        40.13

Test Statistic = F= \frac{75}{40.13} =1.87

Pr(>F) = 0.99986

Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.

3 0
3 years ago
PLEASE HELP 50 POINTS 100 students who are in 10th or 11th grade were asked if they participated in at least one extracurricular
Marina86 [1]

There are 2 variables in this problem. One variable is the class number and other variable is the participation in extracurricular activities. Each variable has further two categories. There are two classes: Class 10 and 11. And students either participate or do not participate in extracurricular activities, which makes 2 categories. 

The best approach to solve this question is to build a table and start entering the given information in it. When the given data has been entered fill the rest on basis of the data you have.

18 students from grade 11 participate in at least one Extracurricular activities. This means the rest students i.e. 22 students from grade 11 do not participate in Extracurricular activities. 

32 students from grade 10 participate in at least one Extracurricular activities. This means total students who participate in at least one Extracurricular activities are 18 + 32 = 50 students.

The rest 50 students do not participate in at least one Extracurricular activities. From these 22 are from class 11. So the rest i.e. 28 are from class 10.

5 0
3 years ago
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