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3 years ago

How would an apple, potato, and onion all taste the same?

Chemistry

1 answer:

Firlakuza [10]3 years ago

6 0

Answer:

If you were to plug your nose, it would block out more than 80% of taste, causing all three items to have no taste- therefore making them taste the same.

Explanation:

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When the oxidation number of an element decreases over the course of a reaction, that element has beenWhich of the following che

NARA [144]

AgNO3+NaCl yields AgCl+NaNo3 (reduction)
...that's the only one I know

4 0

3 years ago

Which statement describes conditions in which a mineral can form?

Alex_Xolod [135]

The answer is A. Hope this helped

8 0

3 years ago

Calculate the feed ratio of adipic acid and hexamethylene diamine that should be employed to obtain a polyamide of approximately

artcher [175]

Answer:

r= 0.9949 (For 15,000)

r=0.995 (For 19,000)

Explanation:

We know that

Molecular weight of hexamethylene diamine = 116.21 g/mol

Molecular weight of adipic acid = 146.14 g/mol

Molecular weight of water = 18.016 g/mol

As we know that when adipic acid and hexamethylene diamine react then nylon 6, 6 comes out as the final product and release 2 molecule of water.

$M_{repeat}=146.14+166.21-2\times 18.106\ g/mol$

$M_{repeat}=226.32\ g/mol$

Mo= 226.32/2 =113.16 g/mol

$M_n=X_nM_o$

Given that

Mn= 15,000 g/mol

15,000 = Xn x 113.16

Xn = 132.55

Now by using Carothers equation we know that

$X_n=\dfrac{1+r}{1+r-2rp}$

$132.55=\dfrac{1+r}{1+r-2\times 0.99r}$

By calculating we get

r= 0.9949

For 19,000

19,000 = Xn x 113.16

Xn = 167.99

By calculating in same process given above we get

r=0.995

3 0

4 years ago

The acid-dissociation constant at 25.0 °c for hypochlorous acid (hclo) is 3.0 ⋅ 10−8. at equilibrium, the molarity of h3o+ in a

maks197457 [2]

Hypochlorous acid is a weak acid. The $K_{a}$ value for the dissociation of HOCl is $3.0 * 10^{-8}$

3 0

3 years ago

How many moles of malachite should be formed when 1.5 moles of copper sulphate reacts with an excess of sodium carbonate?

Katen [24]

2 Na₂CO₃ + 2 CuSO₄ + H₂O → CuCO₃.Cu(OH)₂ + 2 Na₂SO₄ + CO₂
Malachite molar mass = 221.1 g / mol
So 2 moles CuSO₄ produce 1 mole of malachite
so 1.5 mole CuSO₄ produce (0.75) mole malachite
Mass of malachite = 0.75 mole * 221.1 g/ mol = 165.83 g

5 0

4 years ago