Answer:
See below
Explanation:
propane mole weight = 44 gm / mole
100 gm / 44 gm / mole = 2.27 moles
From the equation, 5 times as many moles of OXYGEN (O2)are required
= 11.36 moles of oxygen
at <u>STP</u> this is 254.55 liters of O2 (because 22.4 L = one mole) and
Using oxygen as 21 percent of air means that
.21 x = 254.55 = x = <u>1212.12 liters of air required </u>
Answer:
b)5l x 10kg c)10kg + 9l (Not sure for the last 1)
Camouflage adaptation will most likely help a prey avoid a predator . #answerwithquality #BAL
Mg gained mass because it went from being a single element (on the reactant side) to being a molecule (on the product side).
Answer:
Hi! I believe this is your answer:
52 kilograms
Hope this helps, sorry if it's wrong!
Explanation:
