<span>Which
of the following best describes the electron cloud model?
THE ELECTRON CLOUD MODEL WAS DEVELOPED BY SCHRODINGER. IT STATES THE THE ELECTRONS ARE NOT PARTICLES MOVING AROUND THE NUCLEUS IN FIXED ORBITY BUT THEIR LOCATIONS CAN ONLY BE STATED BY A PROBABILITY DENSITY IN FORM OF CLOUD AROUND THE NUCLEUS.
THEN THE MAIN POINT OF THE CLOUD MODEL IS THAT THE ELECTRONS ARE NOT IN FIXED ORBITS AROUND THE NUCLEUS BUT THEIR LOCATION IS STATED BY A PROBABILITY FUNCTION THAT IS LIKE A CLOUD REGION.
A. It shows
that electrons usually carry a negative charge.
FALSE: ELECTRONS ALWAYS CARRY NEGATIVE CHARGE
B. It shows that
electrons remain in high-energy subshells.
FALSE: ELECTRONS OCCUPY THE LOWEST-ENERGY SUBSHELLS AVAILABLE UNLESS THEY ARE EXCITED (ABSORB ENERGY)
C. It shows that electrons
move quickly in circular orbits.
FALSE: ELECTRONS DO NOT MOVE IN CIRCULAR ORBITS.
D. It shows that the electrons within
an atom do not have sharp boundaries.
TRUE. THE IDEA OF A CLOUD IS A DIFFUSSE REGION WHERE IS A 90% OF PROBABILITIES TO FIND THE ELECTRON, AND THEY DO NOT HAVE SHARP BOUNDARIES.
</span>
Lassa fever is extremely dangerous (please note researchers have a rough time correctly determing how dangerous a virus is because many have not had a major outbreak and a vrius will react differently to everyones body.)
Answer:
I think its 1.2 cause I divided 15.5 with 12 and got 1.2 as an answer
Wavelength is 6.976 x 10^ -35 m
Explanation:
In this, we can use De Broglie’s equation. This equation is the relationship between De Broglie’s wavelength, velocity and the mass of a moving object. In this equation, we are using plank's constant which is 6.626 x 10^-34 m^2 kg/s.
We know that one mile per hour is equivalent to 0.447 M/S.
And One gram is equivalent to 10^-3 kg.
De Broglie’s wavelength = λ ( wave length) = Plank’s constant/ Mass x velocity
λ ( wave length) = 6.626 x 10^ -34/ (425 x10^-3) x ( 50 x 0.447)
= 6.626 x 10^ -34/ 0. 425 x 22.35
= 6.626 x 10^ -34/ 9.498
= 6.976 x10^ -35 m
So, the wavelength of the football will be 6.976 x 10^ -35 m
