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kompoz [17]
3 years ago
6

g .For each of the following disubstituted cyclohexanes, indicate whether the substituents in the two chair conformations would

be both equatorial in one chair conformer and both axial in the other, or one equatorial and one axial in each of the two chair conformers. (a) Cis-1,2- (b) Trans-1,2- (c) Cis-1,3- (d) Trans-1,3- (e) Cis-1,4- (f) Trans-1,4-
Chemistry
1 answer:
Kryger [21]3 years ago
7 0

Answer:

a) Both chairs conformers have one of its substituents in an axial position and the other in an equatorial position

b) One chair conformer has both its substituents in an axial position while the other chair has its substituents in an equatorial position

c) One chair conformer has both its substituents in an axial position while the other chair has its substituents in an equatorial position

d) Both chairs have one of its substituents in an axial position and the other in an equatorial position

e) Both chairs have one of its substituents in an axial position and the other in an equatorial position

(f) One chair conformer has both its substituents in an axial position while the other chair has its substituents in an equatorial position

Explanation:

Determine what the substituents would be

a) Cis-1,2-  : Both chairs conformers have one of its substituents in an axial position and the other in an equatorial position

b) Trans-1,2- : One chair conformer has both its substituents in an axial position while the other chair has its substituents in an equatorial position

c) Cis-1,3- : One chair conformer has both its substituents in an axial position while the other chair has its substituents in an equatorial position

d) Trans-1,3- : Both chairs have one of its substituents in an axial position and the other in an equatorial position

e) Cis-1,4- : Both chairs have one of its substituents in an axial position and the other in an equatorial position

(f) Trans-1,4- : One chair conformer has both its substituents in an axial position while the other chair has its substituents in an equatorial position

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For each of the following pairs of complexes, identify which one you would predict to have the larger Δo value, and explain why.
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Answer:

a) [Fe(H2O)6]3+

b) [Fe(CN)6]3−

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Explanation:

. [Mn(H2O)6]2+ or [Fe(H2O)6]3+

The both complexes are d5 complexes with the same ligand , water. Water is a weak ligand and note that Mn^2+ often have a crystal field stabilization energy of zero hence

[Fe(H2O)6]3+ will possess a greater ∆o value.

The splitting of d orbitals according to the crystal field theory depends on the;

i)geometry of the complex

ii) nature of the metal ion,

iii)charge on the metal ion,

iv) ligands that surround the metal ion.

When the geometry and the ligands are held constant, the order of crystal field splitting is as follows;

Pt4+ > Ir3+ > Rh3+ > Co3+ > Cr3+ > Fe3+ > Fe2+ > Co2+ > Ni2+ > Mn2+

[Fe(H2O)6]3+ or [Fe(CN)6]3−

[Fe(CN)6]3− will have a greater ∆o because the cyanide ion is a strong field ligand compared to water. A strong field ligand causes a greater splitting of the octahedral crystal field compared to a weak field ligand.

. [Fe(CN)6]3− or [Ru(CN)6]3-

[Ru(CN)6]3- will exhibit a greater crystal field splitting. Crystal field splitting increases with the second and third row transition elements when compared to the crystal field splitting of the first row transition elements. Note that, there is an increase of approximately 30%–50% in Δo on going from a first-row transition metal to a second-row metal and another 30%–50% increase on going from a second-row to a third-row metal when they have the same geometry and oxidation state.

4 0
3 years ago
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vesna_86 [32]

Answer:

1.44 g

Explanation:

From the question given above, the following data were obtained:

Number of mole of HCl = 0.06 mole

Mass of Mg =?

From the question given above, we discovered the number of mole of HCl is equivalent to the number of mole of Mg. Thus,

Number of mole of Mg = number of mole of HCl

Number of mole of Mg = 0.06 mole

Finally, we shall determine the mass of Mg. This can be obtained as follow:

Number of mole of Mg = 0.06 mole

Molar mass of Mg = 24 g/mol

Mass of Mg =?

Mass = mole × molar mass

Mass of Mg = 0.06 × 24

Mass of Mg = 1.44 g

Therefore, the mass of magnesium is 1.44 g

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