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mr_godi [17]
1 year ago
11

Kira dissolved different solutes in 100 ml of water. She recorded the amount of each solute that would dissolve at different tem

peratures. What information will this investigation confirm?.
Chemistry
1 answer:
Radda [10]1 year ago
8 0
This information confirms that temperature and solubility are related. The higher the temperature is, the more soluble.
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marishachu [46]

Answer:

A

Explanation:

the measure of a system's thermal energy per unit temperature that is unavailable for doing useful work.

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its d because it has to be diagnoly to the right

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How many moles of Ar gas are<br> present in a container with a<br> volume of 78.4 L at STP?
rusak2 [61]
<h3><u>Answer:</u></h3>

<u>1 mole of a gas at STP occupies 22.4 L volume </u>

<u>Now the volume is given =78.4 therefore,</u>

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<u>I hope it helps you~</u>

7 0
2 years ago
Please Help, will give 30 points! The following data was collected when a reaction was performed experimentally in the laborator
Sedaia [141]

Answer:

9 moles of NaNO3.

Explanation:

The balanced equation for the reaction is given below:

Al(NO3)3 + 3NaCl —> 3NaNO3 + AlCl3

Next, we shall determine the number of mole of Al(NO3)3 and NaCl that reacted and the number of mole of NaNO3 produced from the balanced equation.

From the balanced equation above,

1 mole of Al(NO3)3 reacted with 3 moles of NaCl to produce 3 moles of NaNO3.

Next, we shall determine the limiting reactant.

The limiting reactant can be obtained as follow:

From the balanced equation above,

1 mole of Al(NO3)3 reacted with 3 moles of NaCl.

Therefore, 4 moles of Al(NO3)3 will react with = (4 x 3)/1 = 12 moles of NaCl.

From the calculations made above, we can see that it will take a higher amount i.e 12 moles than what was given i.e 9 moles of NaCl to react completely with 4 moles of Al(NO3)3.

Therefore, NaCl is the limiting reactant and Al(NO3)3 is the excess reactant.

Finally, we shall determine the maximum amount of NaNO3 produced from the reaction.

In this case, the limiting reactant will be used as it will produce the maximum amount of NaNO3 since all of it is consumed by the reaction.

The limit reactant is NaCl and the maximum amount of NaNO3 produced can be obtained as follow:

From the balanced equation above,

3 moles of NaCl reacted to produce 3 moles of NaNO3.

Therefore, 9 moles of NaCl will also react to produce 9 moles of NaNO3.

From the calculations made above, the maximum amount of NaNO3 produced is 9 moles

6 0
3 years ago
Name Formula: Lead (II) Oxide<br> F) Pb2O<br><br> G) PbO2<br><br> H) PbO<br><br> I) Pb2O2
garik1379 [7]

Answer:

PbO is the Answer

Explanation:

4 0
3 years ago
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