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3 years ago

How many atoms of silver are present in one mole of silver

Chemistry

1 answer:

Novay_Z [31]3 years ago

7 0

Answer:

Multiply the mass of the silver atom with avagadro no you will get the no of atoms .

Explanation:

suppose 0.25 moles are silver are multiplied with 6.02*10^23 , you will get the atoms of silver element

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Which of the compounds, c3h8, mgcl2, zn(no3)2, ocl2, are expected to exist as molecules?

fenix001 [56]

The answer is C3H8 and OCl2 they are molecular compounds. MgCl2 is an ionic compound while Zn(NO3)2 is an inorganic chemical compound.
Molecular compounds are covalent compounds in which the elements share electrons via covalent bonds. They are inorganic compounds that take the form of discrete molecules, for example water and carbon dioxide.

4 0

4 years ago

Read 2 more answers

How many moles is 2.2 x 1023 atoms of Fe?

kow [346]

Answer:

it's 3.77 moles

Explanation:

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3 years ago

CH4 + O2 → CO2 + H2O

Scilla [17]

Answer:

9.8 × 10²⁴ molecules H₂O

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Organic

Naming carbons

Stoichiometry

Analyzing reaction rxn
Using Dimensional Analysis

Explanation:

Step 1: Define

[RxN - Unbalanced] CH₄ + O₂ → CO₂ + H₂O

[RxN - Balanced] CH₄ + 2O₂ → CO₂ + 2H₂O

[Given] 130 g CH₄

Step 2: Identify Conversions

Avogadro's Number

[RxN] 1 mol CH₄ → 2 mol H₂O

[PT] Molar Mass of C: 12.01 g/mol

[PT] Molar Mass of H: 1.01 g/mol

Molar Mass of CH₄: 12.01 + 4(1.01) = 16.05 g/mol

Step 3: Stoichiometry

[DA] Set up conversion: $\displaystyle 130 \ g \ CH_4(\frac{1 \ mol \ CH_4}{16.05 \ g \ CH_4})(\frac{2 \ mol \ H_2O}{1 \ mol \ CH_4})(\frac{6.022 \cdot 10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 9.75526 \cdot 10^{24} \ molecules \ H_2O$

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

9.75526 × 10²⁴ molecules H₂O ≈ 9.8 × 10²⁴ molecules H₂O

8 0

3 years ago

orbital cellulitis 5462 children included for study, 1347 (24%) were prescribed corticosteroids within 2 days of admission

son4ous [18]

It's unable to identify a decrease in LOS linked to corticosteroid exposure during hospitalization for ocular cellulitis in this database search. After two days of hospitalization, operational episodes and the prescription of corticosteroids were related to admission to the PICU.

Within two days of admission, 1347 (24%) of the 5462 children who were included in the research received a corticosteroid prescription. In analyses that controlled for age, the existence of meningitis, abscess, or visual problems, as well as the surgical episode and PICU admission within 2 days, corticosteroid prescription was not linked with LOS (e = 1.01, 95% confidence interval [CI]: 0.97-1.06). Among patients with a primary diagnosis of orbital cellulitis, corticosteroid exposure was linked to surgical events after two days of hospitalization (odds ratio = 2.05, 95% CI: 1.29-3.27) and 30-day readmission (odds ratio = 2.40, 95% CI: 1.52-3.78). Prospective, randomized control trials are required prior to the widespread usage of corticosteroids.

Learn more about orbital cellulitis here:-

brainly.com/question/15572218

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4 0

2 years ago

What type of bond is this combination likely to form

kari74 [83]

Answer:

A combination is certainly possible, but you should not take formal charges so literally

Normally, when a covalent bond is found, the two atoms both bring in one electron. As you identify correctly, in the case of nitric acid that would not be possible completely. If you draw the different possible resonance structures, the most likely structure has a single bond between the nitrogen and an oxygen where the oxygen has 3 lone pairs and both electrons in the bond are donated by the nitrogen. This makes the nitrogen "positive" and that oxygen "negative", but in fact the electrons move more freely in the molecule and charges are more distributed. You will not be able to find "the negatively charged" oxygen atom.

Explanation:

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4 0

3 years ago