Answer:
ΔG = 16.218 KJ/mol
Explanation:
- dihydroxyacetone phosphate ↔ glyceraldehyde-3-phosphate
∴ ΔG° = 7.53 KJ/mol * ( 1000 J / KJ ) = 7530 J/mol
∴ R = 8.314 J/K.mol
∴ T = 298 K
∴ Q = [glyceraldehyde-3-phosphate] / [dihydroxyacetone phosphate]
⇒ Q = 0.00300 / 0.100 = 0.03
⇒ ΔG = 7530J/mol - (( 8.314 J/K.mol) * ( 298 K ) * Ln ( 0.03 ))
⇒ ΔG = 16217.7496 J/mol ( 16.218 KJ/mol )
Answer : The molarity of
in the solution is 1.5 M.
Explanation : Given,
Moles of
= 3.0 mol
Volume of solution = 2.00 L
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :

Now put all the given values in this formula, we get:

Therefore, the molarity of
in the solution is 1.5 M.
Answer:
9.35g
Explanation:
The molarity equation establishes that:

So, we have information about molarity (2M) and volume (80 ml=0.08 l), with that, we can find the moles of solute:


The mathematical equation that establishes the relationship between molar weight, mass and moles is:


We have MW (58.44g/mole) and n (0.16 mol), and we need to find m (grams of salt needed) to solve the problem:

Your answer is C. Sublimation :)(
Answer:
Explanation:
2Al(s) + 3 2 O2(g) → Al2O3(s) And given the stoichiometry ...and EXCESS dioxygen gas...we would get 6.25⋅ mol of alumina. the which represents a mass... ...6.25 ⋅ mol ×101.96 ⋅ g ⋅ mol−1 molar mass of alumina ≡ 637.25 ⋅ g.