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Lapatulllka [165]
2 years ago
6

What is the smallest unit of a compound like carbon dioxide (CO2), water (H2O), nitrogen dioxide (NO2) that still have all the p

roperties of that compound? Choose the answer below.
A: a nucleus
B: an atom
C: an element
D: a molecule
Chemistry
2 answers:
pogonyaev2 years ago
7 0
D

Hope this is helpful
spayn [35]2 years ago
6 0
D


Hope this helps


Mark brainliest please
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A factor that keeps a population size from growing too large is called a ______ _______.
Liula [17]

Answer:

limiting factor i think

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3 years ago
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Convert 45 kL to mL (must show work)​
svp [43]

Answer:

1 kiloliter = 1,000,000 milliliters

45 × 1,000,000

45 KL = 45,000,000 ML

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2 years ago
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The substance that is doing the dissolving is referred to as?
ella [17]

Answer:

hi! I'm pretty sure your answer is solvent!

Explanation:

not 100% sure but I looked it up on google. solvent does the dissolving, solute is what is being dissolved, and a solution is the solvent + the solute. hope this helped!

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3 years ago
A student sees a commercial that claims a new dishwasher is energy efficient. Compared to less efficient dishwashers, this means
zaharov [31]
It’s either a or b but I’m not sure
4 0
2 years ago
What is the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from an energy level with n =
Lady bird [3.3K]

Answer:

4.86\times10^{-7}\ \text{m}

Explanation:

R = Rydberg constant = 1.09677583\times 10^7\ \text{m}^{-1}

n_1 = Principal quantum number of an energy level = 2

n_2 = Principal quantum number of an energy level for the atomic electron transition = 4

Wavelength is given by the Rydberg formula

\lambda^{-1}=R\left(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\right)\\\Rightarrow \lambda^{-1}=1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\\\Rightarrow \lambda=\left(1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\right)^{-1}\\\Rightarrow \lambda=4.86\times10^{-7}\ \text{m}

The wavelength of the light emitted is 4.86\times10^{-7}\ \text{m}.

6 0
2 years ago
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