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3 years ago

Diamond has a density of 3.26 g/cm^3. What is the mass of a diamond that has a volume of 0.351 cm^3?

1 answer:

8 0

To approximate the mass of diamond, we use the data on density and the volume of the substance. Density is the mass of a substance over the volume it occupies. The given is 3.26 g/cm3 density and a volume of 0.351 cm3. We multiply the two to get 1.144 grams of diamond.

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Which of the following is a direct result of hydrogen bonding?

prisoha [69]

Cohesion and adhesion

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3 years ago

When beryllium ion combines with carbonate ion, the numbers of each ion are??

Katyanochek1 [597]

Answer:

One of each

Explanation:

Be is in Group 2, so it loses its two valence electrons in a reaction to form Be²⁺ ions.

Carbonate ion has the formula CO₃²⁻.

We can use the criss-cross method to work out the formula of beryllium carbonate.

The steps are

Write the symbols of the anion and cation.

Criss-cross the numbers of the charges to become the subscripts of the other ion.

Write the formula with the new subscripts.

Divide the subscripts by their highest common factor.

Omit all subscripts that are 1.

When you use this method with Be²⁺ and CO₃²⁻, you might be tempted to write the formula for the beryllium carbonate as Be₂(CO₃)₂

However, you can divide the subscripts by their largest common factor (2).

This gives you the formula Be₁(CO₃)₁.

We omit subscripts that are 1, so the correct formula is

BeCO₃

There is one Be²⁺ ion and one CO₃²⁻ ion in a formula unit of beryllium carbonate.

4 0

4 years ago

How many milli liters are needed?

scZoUnD [109]

Answer:

8 ang kylangan ntin hindi ko alam

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3 years ago

For the following reaction, KP = 0.455 at 945°C: At equilibrium, is 1.78 atm. What is the equilibrium partial pressure of CH4 in

Alborosie

Answer:

See explanation below

Explanation:

The question is incomplete. However, here's the missing part of the question:

"For the following reaction, Kp = 0.455 at 945 °C:

C(s) + 2H2(g) <--> CH4(g).

At equilibrium the partial pressure of H2 is 1.78 atm. What is the equilibrium partial pressure of CH4(g)?"

With these question, and knowing the value of equilibrium of this reaction we can calculate the partial pressure of CH4.

The expression of Kp for this reaction is:

Kp = PpCH4 / (PpH2)²

We know the value of Kp and pressure of hydrogen, so, let's solve for CH4:

PpCH4 = Kp * PpH2²

*: You should note that we don't use Carbon here, because it's solid, and solids and liquids do not contribute in the expression of equilibrium, mainly because their concentration is constant and near to 1.

Now solving for PpCH4:

PpCH4 = 0.455 * (1.78)²

PpCH4 = 1.44 atm

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3 years ago

What process causes the banks of the Dead Sea to look the way they do?

alexandr402 [8]

As the warm water holds more salt then cold water the fingers cool and produce crystals of salt that soon rains down to the floor of the ocean

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3 years ago