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Sergeeva-Olga [200]

4 years ago

15

Bart ran 5000 meters from the cops and an average speed (velocity) of 6 meters/ second before he got caught. how long did he run

?

1 answer:

blagie [28]4 years ago

4 0

Answer: 833.333

Explanation:Trust in the process

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A harmonic wave is traveling along a rope. It is observed that the oscillator that generates the wave completes 37.0 vibrations

Goryan [66]

Answer:

0.47 m

Explanation:

$N$ = Number of vibrations = 37

$t$ = total time taken = 33 s

$T$ = time period of each vibration

frequency of vibration is given as

$f = \frac{N}{t} \\f = \frac{37}{33} \\f = 1.12$ Hz

$d$ = distance traveled along the rope = 421 cm = 4.21 m

$t$ = time taken to travel the distance = 8 s

$v$ = speed of the wave

Speed of the wave is given as

$v = \frac{d}{t}\\v = \frac{4.21}{8}\\v = 0.53 ms^{-1}$

$\lambda$ = wavelength of the harmonic wave

wavelength of the harmonic wave is given as

$\lambda = \frac{v}{f} \\\lambda = \frac{0.53}{1.12} \\\lambda = 0.47 m$

8 0

3 years ago

Read 2 more answers

What is the electric potential v due to the nucleus of hydrogen at a distance of 5.292×10−11 m ?

viktelen [127]

Answer: 27.21 V

Explanation:

The <u>electric potential</u> $V_{E}$ due to a point charge is expressed as:

$V_{E}=k\frac{q}{r}$

Where:

$k=9(10)^{9}\frac{Nm^{2}}{C^{2}}$ is the <u>electric constant</u>

$q=1.6(10)^{-19}C$ is the <u>electric charge of the hydrogen nucleus</u>, which is positive

$r=5.292(10)^{-11}m$ is the <u>distance</u>

Rewritting the equation with the known values:

$V_{E}=9(10)^{9}\frac{Nm^{2}}{C^{2}}\frac{1.6(10)^{-19}C}{5.292(10)^{-11}m}$

Finally:

$V_{E}=27.21 V$

5 0

4 years ago

A ray of light has a wavelength of

MArishka [77]

Answer:

The wavelength in vacuum is equal to 428.8 nm.

Explanation:

Given that,

The wavelength of light, $\lambda=284\ nm$

The refractive index of glass, n = 1.51

We need to find the wavelength in vacuum. The relation between wavelength and refractive index is given by :

$n=\dfrac{\lambda_v}{\lambda}\\\\\lambda_v=n\times \lambda\\\\\lambda_v=1.51\times 284\\\\\lambda_v=428.8\ nm$

So, the wavelength in vacuum is equal to 428.8 nm.

6 0

3 years ago

Rainwater draining from a neighborhood street initially travels at 4 ft/s through a pipe with a cross-sectional area of 15.7 ft2

Fudgin [204]

Answer:

The velocity is $v_2 = 0.96 \ ft/s$

Explanation:

From the question we are told that

The initial speed is $v_1 = 4 \ ft/s$

The cross -sectional area of the first pipe is $A_1 = 15.7 \ ft$

The cross -sectional area of the second pipe is $A_2 = 65.4 \ ft$

Generally from continuity equation we have that

$A_1 * v_1 = A_2 * v_2$

So

$v_2 = \frac{A_1 * v_1 }{A_2 }$

=> $v_2 = \frac{15.7 * 4 }{65.4 }$

=> $v_2 = 0.96 \ ft/s$

6 0

4 years ago

Devon has several toy car bodies and motors. The motors have the same mass, but they provide different amounts of force, as show

Grace [21]

Answer:

pretty sure its motor 2, with body 1

Explanation:

4 0

3 years ago

Read 2 more answers