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zhannawk [14.2K]
3 years ago
11

A. What is the frequency of blue light that has a wavelength of 450 nm?

Physics
1 answer:
erastova [34]3 years ago
3 0

Answer

a)Given,

Wavelength of blue light = 450 n m = 450 x 10⁻⁹ m

 Speed of light = 3 x 10⁸ m/s

we know,

       c = \nu \lambda

       \nu = \dfrac{c}{\lambda}

       \nu = \dfrac{3\times 10^8}{450\times 10^{-9}}

      \nu = 6.67 \times 10^{14}\ Hz

b)Given,

Wavelength of red light = 650 n m = 650 x 10⁻⁹ m

 Speed of light = 3 x 10⁸ m/s

we know,

       c = \nu \lambda

       \nu = \dfrac{c}{\lambda}

       \nu = \dfrac{3\times 10^8}{650\times 10^{-9}}

      \nu = 4.62 \times 10^{14}\ Hz

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Answer:

a) v = 1.075*10^7 m/s

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Explanation:

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K=qV          (1)

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You replace the values of the parameters in the equation (1):

K=(3.2*10^{-19}C)(1.2*10^6V)=3.84*10^{-13}J

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v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(3.84*10^{-13}J)}{6.64*10^{-27}kg}}\\\\v=1.075*10^7\frac{m}{s}

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b) The magnetic force on the particle is given by:

|F_B|=qvBsin(\theta)

B: magnitude of the magnetic field = 2.2 T

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|F_B|=(3.2*10^{-19}C)(1.075*10^6m/s)(2.2T)=7.57*10^{-12}N

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c) The particle describes a circumference with a radius given by:

r=\frac{mv}{qB}=\frac{(6.64*10^{-27}kg)(1.075*10^7m/s)}{(3.2*10^{-19}C)(2.2T)}\\\\r=0.101m=10.1cm

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