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zhannawk [14.2K]
3 years ago
11

A. What is the frequency of blue light that has a wavelength of 450 nm?

Physics
1 answer:
erastova [34]3 years ago
3 0

Answer

a)Given,

Wavelength of blue light = 450 n m = 450 x 10⁻⁹ m

 Speed of light = 3 x 10⁸ m/s

we know,

       c = \nu \lambda

       \nu = \dfrac{c}{\lambda}

       \nu = \dfrac{3\times 10^8}{450\times 10^{-9}}

      \nu = 6.67 \times 10^{14}\ Hz

b)Given,

Wavelength of red light = 650 n m = 650 x 10⁻⁹ m

 Speed of light = 3 x 10⁸ m/s

we know,

       c = \nu \lambda

       \nu = \dfrac{c}{\lambda}

       \nu = \dfrac{3\times 10^8}{650\times 10^{-9}}

      \nu = 4.62 \times 10^{14}\ Hz

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Many people drink 2 cans of coke each day. If each can has 39 grams of sugar, how many pounds of sugar is consumed each week? Gi
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A sealed tank containing seawater to a height of 12.8 m also contains air above the water at a gauge pressure of 2.90 atm . Wate
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Answer:

The velocity of water at the bottom, v_{b} = 28.63 m/s

Given:

Height of water in the tank, h = 12.8 m

Gauge pressure of water, P_{gauge} = 2.90 atm

Solution:

Now,

Atmospheric pressue, P_{atm} = 1 atm = 1.01\tiems 10^{5} Pa

At the top, the absolute pressure, P_{t} = P_{gauge} + P_{atm} = 2.90 + 1 = 3.90 atm = 3.94\times 10^{5} Pa

Now, the pressure at the bottom will be equal to the atmopheric pressure, P_{b} = 1 atm = 1.01\times 10^{5} Pa

The velocity at the top, v_{top} = 0 m/s, l;et the bottom velocity, be v_{b}.

Now, by Bernoulli's eqn:

P_{t} + \frac{1}{2}\rho v_{t}^{2} + \rho g h_{t} = P_{b} + \frac{1}{2}\rho v_{b}^{2} + \rho g h_{b}

where

h_{t} -  h_{b} = 12.8 m

Density of sea water, \rho = 1030 kg/m^{3}

\sqrt{\frac{2(P_{t} - P_{b} + \rho g(h_{t} - h_{b}))}{\rho}} =  v_{b}

\sqrt{\frac{2(3.94\times 10^{5} - 1.01\times 10^{5} + 1030\times 9.8\times 12.8}{1030}} =  v_{b}

v_{b} = 28.63 m/s

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