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zhannawk [14.2K]
3 years ago
11

A. What is the frequency of blue light that has a wavelength of 450 nm?

Physics
1 answer:
erastova [34]3 years ago
3 0

Answer

a)Given,

Wavelength of blue light = 450 n m = 450 x 10⁻⁹ m

 Speed of light = 3 x 10⁸ m/s

we know,

       c = \nu \lambda

       \nu = \dfrac{c}{\lambda}

       \nu = \dfrac{3\times 10^8}{450\times 10^{-9}}

      \nu = 6.67 \times 10^{14}\ Hz

b)Given,

Wavelength of red light = 650 n m = 650 x 10⁻⁹ m

 Speed of light = 3 x 10⁸ m/s

we know,

       c = \nu \lambda

       \nu = \dfrac{c}{\lambda}

       \nu = \dfrac{3\times 10^8}{650\times 10^{-9}}

      \nu = 4.62 \times 10^{14}\ Hz

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Unless you have a diagram to include or any other additional info, I'll assume the block is being pulled by two opposing forces along the horizontal surface.

Horizontally, the block is under the influence of

• one rope pulling in one direction with magnitude 15 N,

• the other rope pulling in the opposite direction with mag. 5 N, and

• friction, opposing the direction of the block's motion, with mag. 3 N.

It stands to reason that the block is accelerating in the direction of the larger pulling force.

(A) By Newton's second law, we have

15 N + (-5 N) + (-3 N) = <em>m</em> (1 m/s²)

where <em>m</em> is the mass of the block. Solve for <em>m</em> :

7 N = <em>m</em> (1 m/s²)

<em>m</em> = (7 N) / (1 m/s²)

<em>m</em> = 7 kg

(B) The friction force is proportional to the normal force, so that if <em>f</em> is the mag. of friction and <em>n</em> is the mag. of the normal force, then <em>f</em> = <em>µ</em> <em>n</em> where <em>µ</em> is the coefficient of friction.

The block does not bounce up and down, so its vertical forces are balanced, which means the normal force and the block's weight (mag. <em>w</em>) cancel out:

<em>n</em> + (-<em>w</em>) = 0

<em>n</em> = <em>w</em>

<em>n</em> = <em>m</em> <em>g</em>

where <em>g</em> = 9.8 m/s² is the mag. of the acceleration due to gravity.

<em>n</em> = (7 kg) (9.8 m/s²)

<em>n</em> = 68.6 N

Then

3 N = <em>µ</em> (68.6 N)

<em>µ</em> = (3 N) / (68.6 N)

<em>µ</em> ≈ 0.044

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2 years ago
A hot air balloon contains 85,000 moles of air. To what temperature must the
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Answer:

B is the best answer for this question

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A laser with a power of 1.0 mW has a beam radius of 1.0 mm. What is the peak value of the electric field in that beam
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Answer:

The peak value of the electric field is 489.64 V/m

Explanation:

Given;

power of the laser, P = 1.0 mW = 1 x 10⁻³ W

Radius of the beam, R = 1.0 mm = 1 x 10⁻³ m

Area of the beam = πr² = π(1 x 10⁻³ )² = 3.142 x 10⁻⁶ m²

The average intensity of the light = P / A

The average intensity of the light = ( 1 x 10⁻³) / (3.142 x 10⁻⁶)

The average intensity of the light = 318.27 W/m²

The peak value of the electric field is given by;

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Therefore, the peak value of the electric field is 489.64 V/m.

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Answer:

the correct answer is 273.2 k

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Which of the following best describes what muscles do.
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I think b support body weight

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