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Mkey [24]
2 years ago
5

List out any 4 objectives of education​

Physics
1 answer:
e-lub [12.9K]2 years ago
6 0
- vocational aim
- cultural aim
- spiritual aim
- intellectual aim
You might be interested in
Astronomers determine that a certain square region in interstellar space has an area of approximately 2.4 \times 10^72.4×10 ​7 ​
mafiozo [28]

Answer:

1.5 × 10³⁶ light-years

Explanation:

A certain square region in interstellar space has an area of approximately 2.4 × 10⁷² ​​ (light-years)². The area of a square can be calculated using the following expression.

A = l²

where,

A is the area of the square

l is the side of the square

l = √A = √2.4 × 10⁷² ​​ (light-years)² = 1.5 × 10³⁶ light-years

5 0
3 years ago
Fill in the table below with the properties of acids and bases.
Whitepunk [10]

Answer:

1) Acids have a sour taste , Bases have a bitter taste.

2) Acids turn blue litmus paper into red , Bases turn red litmus paper into blue.

3) Acids react with most metals to form Hydrogen gas but only a few base react with a few metals to form Hydrogen gas

4) Both will conduct electricity. Both acids & bases are good electrolytes. Strong acids & bases conduct more electricity than that of weak acids & bases

5 0
3 years ago
This time particle A starts from rest and accelerates to the right at 65.5 cm/s
FrozenT [24]

Answer:

t = 4 s

Explanation:

As we know that the particle A starts from Rest with constant acceleration

So the distance moved by the particle in given time "t"

d = v_i t + \frac{1}{2}at^2

d = 0 + \frac{1}{2}(65.5)t^2

d_1 = 32.75 t^2 cm

Now we know that B moves with constant speed so in the same time B will move to another distance

d_2 = 44 \times t

now we know that B is already 349 cm down the track

so if A and B will meet after time "t"

then in that case

d_1 = 349 + d_2

32.75 t^2 = 349 + 44 t

on solving above kinematics equation we have

t = 4 s

4 0
3 years ago
2. Tony sets up an experiment inside his classroom. He spaces 5 plants at equal
brilliants [131]

Answer:

a

Explanation:

4 0
3 years ago
Read 2 more answers
Find the speed of light in each of the following materials. (a) gallium phosphide m/s (b) carbon disulfide m/s (c) benzene
Oksanka [162]

Explanation:

We need to calculate the speed of light in each materials

(I). Gallium phosphide,

The index of refraction of Gallium phosphide is 3.50

Using formula of speed of light

v=\dfrac{c}{\mu}....(I)

Where, \mu = index of refraction

c = speed of light

Put the value into the formula

v=\dfrac{3\times10^{8}}{3.50}

v=8.6\times10^{7}\ m/s

(II) Carbon disulfide,

The index of refraction of Gallium phosphide is 1.63

Put the value in the equation (I)

v=\dfrac{3\times10^{8}}{1.63}

v=1.8\times10^{8}\ m/s

(III). Benzene,

The index of refraction of Gallium phosphide is 1.50

Put the value in the equation (I)

v=\dfrac{3\times10^{8}}{1.50}

v=2\times10^{8}\ m/s

Hence, This is the required solution.

7 0
3 years ago
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