Answer:
<em> I can't see the picture</em>
Explanation:
Answer:
<em>D.) Object 1 has 4x the kinetic energy of object 2</em>
Explanation:
<u>Kinetic Energy
</u>
Is the type of energy an object has due to its state of motion. It is proportional to the square of the speed.
The formula for the kinetic energy is:
Where:
m = mass of the object
v = speed at which the object moves
Now suppose we have two objects with the same mass m1=m2=m and object 1 moves twice as fast as object 2, that is:
Let's compute their kinetic energies:
Since v1=2v2, the first kinetic energy is:
Dividing both equations:
Simplifying:
Or, equivalently:
Answer:
D.) Object 1 has 4x the kinetic energy of object 2
1. It depends on the condition you are referring to
I mean if you drop a sphere and a thin copper plate both of same mass from the Mt Everest. both will have different velocity and time period to fall on the ground because both of them experiences a drag force upwards due to their shape the more the area you have the more the drag Force if thus the lesser the speed and more the time period is
2. if you assume it to be total vaccum then both of them will fall on the same time and with same velocity no matter the mass is different or the shape is ! physics work same for them ..
Question 4
B. Toby is correct because the rock is experiencing a negative acceleration, causing its positive velocity to decrease until the rock reaches a velocity of O m/s before becoming negative.
Question 5
At the maximum height, velocity is 0, so:
v = v₀ - gt
0 = 14.75 - 9.8t
t = 14.75/9.8
t = 1.5 s (OPTION A)
If a potassium atom loses one electron than it becomes a +1 charge, because the electrons are negative and the nucleus is positive (the positive comes from the protons). The protons and electrons balance out so it has a neutral charge, but if the atom loses an electrons it has a positive charge, but if the atom gains an electron than it becomes negative. the charge (+/- and the number) of the atom depends on how many electron the atom gains/loses.
the answer is (D.) +1
I hope this helps.