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mash [69]
3 years ago
8

Estimate the area of a circle with a radius of 16 meters. Use 22/7 or pi

Mathematics
1 answer:
Dmitrij [34]3 years ago
3 0
1. Area of a circle is pi(R)^2 , where R is the radius. So we can substitute:

22/7(16^2) = about 805 meters squared.

2. Let's find the area of the rectangle first.

A=LW
A= 18(10)

A= 180 cm squared.


Now the semi-Circle:

The radius of the circle is 9 (because 18/2 is 9). Now we plug in to the area formula:

22/7(9^2) = about 254 cm squared. But because that is the area of the whole circle, and we only need half of the circle, we divide that value by 2 to get:

127 cm squared for the semi-circle.

Now we add up the rectangle and semi-circle's areas:

180 + 127 = 307 cm squared as your answer.


I hope this Helps!
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PLEASE HELP ME! IM ON A TIMED QUIZZZZ
viktelen [127]

Answer:


Step-by-step explanation:

Part A: 20 shows $20 which Cory earns by mowing one lawn. 9 shows $9 which he earns by trimming one hedge. x shows the number of lawns. y shows the number of hedges. Part B: There are two terms in this expression. 20x which shows the total earning of Cory by mowing lawns. 9y which shows his earning by trimming hedges. It can be judged by the description of rates explained in part A. Part C: From explanation given in Part C, we can easily see that the expression 9y is used for the total earned from trimming hedges.



4 0
3 years ago
Solve for x: −3|x − 3| = −6
lozanna [386]
-3|x-3|=-6
divide both sides by -3
|x-3|=2
assume
x-3=2 and
x-3=-2

x-3=2
add 3
x=5

x-3=-2
add 3
x=1

x=5 or 1
7 0
3 years ago
A package of pairs of insulated costs ​$. What is the unit price of the pairs of
Kobotan [32]

Answer:

$5.89 per pair

$35.34   6 pairs

$35.34/6=$5.89 per pair

4 0
3 years ago
Simplify m(2+n-m)+3(3n+m^2-1)
mina [271]

Answer:2m^2+mn+2m+9n-3

Step-by-step explanation:

m(2+n-m)+3(3n+m^2-1)

open brackets

2m+mn-m^2+9n+3m^2-3

Collect like terms

3m^2-m^2+mn+2m+9n-3

2m^2+mn+2m+9n-3

4 0
3 years ago
the square of a certain whole number n is n^2. if 60 is a factor of n^2, it's possible that ? is not a factor of n^2. a)16 b)25
DanielleElmas [232]
If 60 is a factor of n², then √60 is a factor of n. However, n is a whole number, so its factors are whole numbers.

Simplify √60:
\sqrt{60}=\sqrt{4 \times 15}=2\sqrt{15}

If 2√15 is a factor of a whole number n, then √15 must be another factor to make it a whole number.

2\sqrt{15} \times \sqrt{15}=2 \times 15=2 \times 3 \times 5

If 60 is a factor of n², then 2, 3, and 5 must be factors of n. The factors of n² are the squares of the factors of n, so 2, 2, 3, 3, 5, and 5 must be factors of n².

Now, if 2, 2, 3, 3, 5, and 5 are factors of n², then:
* 5×5=25 must also be its factor
* 2×2×3×3=36 must also be its factor
* 2×2×5×5=100 must also be its factor

Only 16 may not be a factor of n². The answer is A.
4 0
3 years ago
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